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olchik [2.2K]
3 years ago
15

Can someone help me in 5 and 7 please

Mathematics
1 answer:
pav-90 [236]3 years ago
4 0

5

Write -22 in the middle of the graph, number the rest of the graph accordingly and draw an open circle around the line under the -22 and draw a line along the graph to the right


7

Write 15 in the middle of the graph and number the rest of the graph accordingly, draw a colored in circle under the 15 on the graph and draw a line to the to the right


Sorry, I'm on the road and couldn't take a picture of the solution


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HELP ME PLEASE IM SO DESPERATE TO ANSWER THIS, ILL BE SO THANKFUL TO YALL
Scrat [10]

Answer:

x+2 volts is what I got.

Step-by-step explanation:

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3 years ago
arron takes his dog for a walk afer school, he walks 5 blocks east and then 4 blocks north. if he was able to take a direct rout
nlexa [21]

Hi!

We are given the information found in the picture below.

Note: The directions aren't correct, but the triangle works for this problem.

The "direct path" is the hypotenuse of this triangle.

To find this, we use the Pythagorean Theorem, where a and b are 2 legs of the triangle, and c is the hypotenuse, aka the longest side of any triangle:

a^2+b^2=c^2

We know a and b and want c

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3 0
2 years ago
An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let
Advocard [28]

Answer:

P(t)=3,000,000-3,000,000e^{0.0138t}

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

P'(t)=K(3,000,000-P(t))

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

<em>P(0) = 0 and P(50) = 1,500,000 </em>

We have and ordinary differential equation of first order that we can write

P'(t)+KP(t)= 3,000,000K

The <em>integrating factor </em>is

e^{Kt}

Multiplying both sides of the equation by the integrating factor

e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K

Hence

(e^{Kt}P(t))'=3,000,000Ke^{Kt}

Integrating both sides

e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C

e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C

P(t)=3,000,000+Ce^{-Kt}

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

so

e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138

And the equation that models the number of people (in millions) who become aware of the product by time t is

P(t)=3,000,000-3,000,000e^{0.0138t}

5 0
3 years ago
Two lines that intersect at 90 degree angles
Molodets [167]
That would be a right angle 
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The two figures have a scale of 3:1. What is the length of the corresponding side in the second figure?
zhuklara [117]
I will say it will be c
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Read 2 more answers
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