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3 years ago

15

Can someone help me in 5 and 7 please

1 answer:

pav-90 [236]3 years ago

4 0

5

Write -22 in the middle of the graph, number the rest of the graph accordingly and draw an open circle around the line under the -22 and draw a line along the graph to the right

7

Write 15 in the middle of the graph and number the rest of the graph accordingly, draw a colored in circle under the 15 on the graph and draw a line to the to the right

Sorry, I'm on the road and couldn't take a picture of the solution

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HELP ME PLEASE IM SO DESPERATE TO ANSWER THIS, ILL BE SO THANKFUL TO YALL

Scrat [10]

Answer:

x+2 volts is what I got.

Step-by-step explanation:

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3 years ago

arron takes his dog for a walk afer school, he walks 5 blocks east and then 4 blocks north. if he was able to take a direct rout

nlexa [21]

Hi!

We are given the information found in the picture below.

Note: The directions aren't correct, but the triangle works for this problem.

The "direct path" is the hypotenuse of this triangle.

To find this, we use the Pythagorean Theorem, where $a$ and $b$ are 2 legs of the triangle, and $c$ is the hypotenuse, aka the longest side of any triangle:

$a^2+b^2=c^2$

We know $a$ and $b$ and want $c$

$4^2+5^2=c^2$

$16+25=c^2$

$41=c^2$

Therefore, $c$ is approximately $6.403$

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2 years ago

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

<em>P(0) = 0 and P(50) = 1,500,000 </em>

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The <em>integrating factor </em>is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

so

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

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3 years ago

Two lines that intersect at 90 degree angles

Molodets [167]

That would be a right angle

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3 years ago

The two figures have a scale of 3:1. What is the length of the corresponding side in the second figure?

zhuklara [117]

I will say it will be c

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3 years ago

Read 2 more answers