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xeze [42]
3 years ago
14

What is 0.489 in word form please answer

Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

four hundred eighty nine thousandths

Step-by-step explanation:

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Identify the volume of the composite figure. HELP PLEASE!!
Ilya [14]

Answer:

Vol. of the composite figure is 189 m³

Step-by-step explanation:

Find the volume of the larger figure by mult. together its 3 dimensions:

V = (9 m)(8 m)(3 m) = 216 m³.

Next, find the volume of the "notch," which is (3 m)³, or 27 m³.

Finally, subtract the "notch" volume from the 216 m³ volume found earlier:

216 m³ - 27 m³ = 189 m³

4 0
4 years ago
Miguel ordered lunchmeat at the
lutik1710 [3]

Answer:

7.96

Step-by-step explanation:

6 0
3 years ago
Find the least common multiple of 8x³y6z, 6x5z², and<br> 10yzº.
kvv77 [185]

Answer:

The Least Common Multiple (LCM) of 8x^3y6z,6x5z^2, \text{ and } 10yz^0 \text{ is } 240 x^3yz^2

Step-by-step explanation:

<u>Definition of LCM</u>

The LCM of a, b , c is the smallest multiplier that is divisible by a, b and c

Here the three terms are :

8x^3y6z

6x5z^2

10yz^0=10y        since z^0 = 1

Factoring using prime factorization we get  8x^3y6z = 2.2.2.x^3.y.2.3.z³

= 2^4\cdot \:3\cdot \:x^3\cdot \:y\cdot \:z   (1)

Factoring 6x5z^2  we get

2\cdot \:3\cdot \:5\cdot \:x\cdot \:z^2  (2)

Factoring 10yz^0 we get

2 \;\cdot\; 5y                 (z^0 = 1)   (3)

The LCM is the multiple of each of the highest power in each factor

2^4\;.\;3\;.\;5\;.x^2\;.\;y\;.z^2 = 240 x^3yz^2

8 0
2 years ago
The perimeter of a regular hexagon is 6x + 30. What is the length<br> of each side of the hexagon?
Fofino [41]

Answer:

x + 5

Step-by-step explanation:

This is actually rather simple to figure out. Simply divide 6x + 30 by 6. That should get x + 5 for the length of one side.

4 0
3 years ago
Find the value of x. Round your answer to the nearest tenth
Sergio039 [100]

Answer:

Your answer would be 24 but then if you  round it to the nearest tenth the you would have 20

Step-by-step explanation:

i hope this helps

4 0
2 years ago
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