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vladimir1956 [14]
3 years ago
11

A snail travels 10 cm in 4 minutes. At this rate: How long will it take the snail to travel 24 cm?

Mathematics
1 answer:
atroni [7]3 years ago
7 0

It will take the snail 9.6 minutes to travel 24cm.

Step-by-step explanation:

Distance covered in 4 minutes = 10 cm

Ratio of distance to time = 10:4

New distance = 24cm

Let,

x be the time period

Ratio of new distance to time = 24:x

Using proportions;

Ratio of distance to time :: Ratio of new distance to time

10:4::24:x

Product of mean = Product of extreme

24*4=10*x\\96=10x\\10x=96

Dividing both sides by 10

\frac{10x}{10}=\frac{96}{10}\\x=9.6\ minutes

It will take the snail 9.6 minutes to travel 24cm.

Keywords: ratio, proportion

Learn more about ratios at:

  • brainly.com/question/4027296
  • brainly.com/question/4046256

#LearnwithBrainly

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What 2 numbers divide to get 375 while multiplying to equal 38.4?
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Answer:

<em>Well, 375 is a composite number. </em>

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<em>Factors of 375: 1, 3, 5, 15, 25, 75, 125, 375. </em>

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3 years ago
the sum of three numbers is 90. the third number is 4 times the first. the second number is 6 less than the first. what are the
igor_vitrenko [27]

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Step-by-step explanation:

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4 0
2 years ago
Solve the equation <img src="https://tex.z-dn.net/?f=%2835%20x%5E%7B4%7D%20y%2B14%20x%5E%7B5%7D%20y-2%20y%5E%7B3%7D-4x%20y%5E%7B
jeka94
\underbrace{35x^4y+14x^5y-2y^3-4xy^3}_M\,\mathrm dx+\underbrace{7x^5-6xy^2}_N\,\mathrm dy=0

M_y=35x^4+14x^5-6y^2-12xy^2
N_x=35x^4-6y^2

\dfrac{N_x-M_y}N=\dfrac{-14x^5+12xy^2}{7x^5-6xy^2}=-2

This suggests an integrating factor depending on x only is possible, and given by

\mu(x)=\exp\left(-\displaystyle\int\frac{N_x-M_y}N\,\mathrm dx\right)=e^{2x}

Distributing across the ODE, we end up with

\underbrace{(35x^4y+14x^5y-2y^3-4xy^3)e^{2x}}_{M^*}\,\mathrm dx+\underbrace{(7x^5-6xy^2)e^{2x}}_{N^*}\,\mathrm dy=0

The equation is now exact, with

{M^*}_y={N^*}_x=(35x^4+14x^5-6y^2-12xy^2)e^{2x}

Now we find the solution:

F_x=M^*
F=\displaystyle\int(35x^4+14x^5-2y^3-4xy^3)e^{2x}\,\mathrm dx
F=(7x^5y-2xy^3)e^{2x}+f(y)

F_y=N^*
(7x^5-6xy^2)e^{2x}+f'(y)=(7x^5-6xy^2)e^{2x}
f'(y)=0
\implies f(y)=C

The general solution is then

F(x,y)=(7x^5y-2xy^3)e^{2x}=C
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The sum of two consecutive odd integers is 32 what are the two integers
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15 and 17 is the answer
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3 years ago
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