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vladimir1956 [14]
3 years ago
11

A snail travels 10 cm in 4 minutes. At this rate: How long will it take the snail to travel 24 cm?

Mathematics
1 answer:
atroni [7]3 years ago
7 0

It will take the snail 9.6 minutes to travel 24cm.

Step-by-step explanation:

Distance covered in 4 minutes = 10 cm

Ratio of distance to time = 10:4

New distance = 24cm

Let,

x be the time period

Ratio of new distance to time = 24:x

Using proportions;

Ratio of distance to time :: Ratio of new distance to time

10:4::24:x

Product of mean = Product of extreme

24*4=10*x\\96=10x\\10x=96

Dividing both sides by 10

\frac{10x}{10}=\frac{96}{10}\\x=9.6\ minutes

It will take the snail 9.6 minutes to travel 24cm.

Keywords: ratio, proportion

Learn more about ratios at:

  • brainly.com/question/4027296
  • brainly.com/question/4046256

#LearnwithBrainly

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Answer:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

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Step-by-step explanation:

Information given

\bar X_{1}=14 represent the mean for sample 1 (younger)

\bar X_{2}=20 represent the mean for sample 2 (older)  

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=31 sample size for the group 2  

n_{2}=31 sample size for the group 2  

t would represent the statistic

System of hypothesis

We want to test if  that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

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t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

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