Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4
y=ax^2→y=-(1/4)x^2
7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4
Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m
Please, see the attached file.
Answer: Third option 15.75 m
something through 1-10. i think its 7 but i rlly dont know. Sry.
Answer: x = 8
Step-by-step explanation:
This is a very, very, very simple algebra problem. I assume you know the basics of algebra.
First, move 8 to the other side:
3x = 24
divide by 3 on both sides
x = 8
There! Would it kill you to give me a quartic question to spice my life up?
Answer:
B, you are correct
Area of the bigger trapezoid = (6 + 2) x 1/2 x 6 = 8 x 1/2 x 6 = 4 x 6 = 24
Area of the smaller trapezoid = (4 + 2) x 1/2 x 3 = 6 x 1/2 x 3 = 3 x 3 = 9
<h2>Area of the shaded area = 24 - 9 = 15</h2>
<em>Hope that helps! :)</em>
<em>Hope that helps! :)</em>
<em></em>
<em>-Aphrodite</em>
Step-by-step explanation: