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Mnenie [13.5K]
3 years ago
7

Can somebody help me

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0
It is 1a over bd and 8 over k
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Nady [450]

Answer:

tyreagdfasgavgcrec

Step-by-step explanation:

aerbygrsyhbrsvd

6 0
3 years ago
19. The value(s) of x such that<br> f(x) = 11<br> Help please):
In-s [12.5K]

Answer:

Hope you can find your answer on oceanhero

Step-by-step explanation:

3 0
3 years ago
Complete the equations so that the solution of the system of equations is (−1, −4). y= ?X−11 6x− ? Y=10
eimsori [14]

Answer:

y = –7x – 11

6x – 4y = 10

Step-by-step explanation:

From the question given above, we obtained:

x = –1

y = –4

y = ?x – 11 ....... (1)

6x – ?y = 10b......... (2)

Let the two unknown be a and b. Thus the above equation becomes:

y = ax – 11 ......... (3)

6x – by = 10 .......(4)

Next, we shall determine the value of 'a' and 'b'. This can be obtained as follow:

For a:

y = ax – 11

x = –1

y = –4

–4 = a(–1) – 11

–4 = –a – 11

Collect like terms

–4 + 11 = –a

7 = –a

Multiply through by –1

a = –7

For b:

6x – by = 10

x = –1

y = –4

6(–1) – b(–4) = 10

–6 + 4b = 10

Collect like terms

4b = 10 + 6

4b = 16

Divide both side by 4

b = 16 / 4

b = 4

Finally, we shall substitute the value of a and be into equation 3 and 4 respectively.

y = ax – 11

a = –7

y = –7x – 11

6x – by = 10

b = 4

6x – 4y = 10

Therefore, the complete equation are:

y = –7x – 11

6x – 4y = 10

8 0
3 years ago
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
zloy xaker [14]

Answer:

t=-20ln\left(\dfrac{1}{3}\right)

Step-by-step explanation:

The relationship between A, the area of the glacier in square kilometers, and t, the number of years the glacier has been melting, is modeled by the equation.:

A=45e^{-0.05t}

We want to determine the value of t for which the area, A(t)=15 square kilometers.

15=45e^{-0.05t}\\$Divide both sides by 45\\\dfrac{15}{45} =\dfrac{45e^{-0.05t}}{45}\\\dfrac{1}{3}=e^{-0.05t}\\$Take the natural logarithm of both sides\\ln\left(\dfrac{1}{3}\right)=ln\left(e^{-0.05t}\right)\\ln\left(\dfrac{1}{3}\right)=-0.05t\\$Divide both sides by -0.05$\\t=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05} \\=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05}\\t=-20ln\left(\dfrac{1}{3}\right)

Therefore, the time for which the area will be 15 sqyare kilometers is:

-20 ln(1/3) years.

7 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if
andrey2020 [161]

The 34th term of the sequence 158, 155, 152 ...... is 59

The sequence is as follows:

158, 155, 152 ......

let

a = first term = 158

d = common difference = 155 - 158 = -3

Using Arithmetic progression formula, let's find the 34th term as follows:

aₙ = a + (n - 1)d

a₃₄ = 158 + (34 - 1)-3

a₃₄ = 158 + (33)(-3)

a₃₄ = 158 - 99

a₃₄ = 59

Therefore, the 34th term of the sequence is 59.

learn more about sequence here: brainly.com/question/23251262?referrer=searchResults

3 0
2 years ago
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