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Alekssandra [29.7K]
3 years ago
11

A number increased by 7 is 2 less than twice the number

Mathematics
1 answer:
erastovalidia [21]3 years ago
7 0

The answer is 9

9+7=16

9*2=18

18-16=2

Hope this helped!

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Evaluate the following expression using the values given:
MrMuchimi
Replace each letter with it's value, so:
= (5*-2) + (-3*2) + 3
= -10 -6 +3
= -13
6 0
3 years ago
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At the start of the week a bookshop had science and art books in the ratio 2:5. By the end of the week, 20% of each type of book
Anastaziya [24]
Let there be 2x science and 5x art books 
<span>science books sold = 2x × 0.2 = 0.4x </span>
<span>science books unsold = 2x – 0.4x = 1.6x </span>

<span>art books sold = 5x × 0.2 = x </span>
<span>art books unsold = 5x – x = 4x </span>

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5 0
3 years ago
An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

  • a = 10
  • b = 16
  • c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0
2 years ago
A bandleader randomly select's two students out of 100 bandmembers if you and your brother are both bandmembers what is the prob
kherson [118]
<span>There are 100 * 99 = 9900 different ways to choose two students out of 100 bandmembers. You and our brother are 2 of that ways: you being selected first and you being selected second. Therefore the probability that you two are selected is 2 / 9900 = 0,000202. You can also think as the probability of you being selected among 100 bandmembers, which is 1/100, times the probability of your brother being selected among 99 members, which is 1/99 => (1/100) * (1/99) = 1/ (100*99) = 1 / 9900; plus the same for your brother being selected first and you second => [1/9900] * 2 = 2/9900, which is the same calculated above.</span>
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187.36 -0.6 solve this ​
lisov135 [29]
Answer: 187.30

explanation for answer:
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