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inessss [21]
3 years ago
7

Work out the area of a semicircle with radius 3cm. give your answer in terms of 3.142

Mathematics
2 answers:
telo118 [61]3 years ago
4 0

1.5 • 3.142= 4.713 should be the answer

Lilit [14]3 years ago
4 0

Answer:   4.5π  ≈  14.14 cm²

<u>Step-by-step explanation:</u>

Area_{\ circle}=\pi \cdot r^2\\\\Area_{\ semicircle}=Area_{\ circle}\div 2\\\\\\A=\dfrac{\pi \cdot 3^2}{2}\\\\\\.\quad =\dfrac{9}{2}\pi\\\\\\.\quad =4.5\pi\\\\\\.\quad =14.14

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3 0
3 years ago
Which is a correct two-column proof?<br> Given: ∠h and ∠c are supplementary.<br> Prove: j || l
pentagon [3]

Answer:

Third option is the correct answer.

Step-by-step explanation:

Third option is the correct answer.

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3 years ago
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Juli2301 [7.4K]

Answer:

3. 4x^2y

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2 years ago
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4 0
2 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6
faltersainse [42]

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between​ the carrier's highest data speed and the mean of all 50 data​ speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the​ carrier's highest data speed to a z score.

The value is X= 76.6

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d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly​ high, is the​ carrier's highest data speed​ significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!

3 0
3 years ago
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