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Hitman42 [59]
3 years ago
11

Which statement about y = x2 + 7x - 30 is true?

Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

D. The zeros are 3 and -10, because y = (x - 3)(x + 10).

Step-by-step explanation:

y=x^2+7x-30

0=x^2+7x-30

0=(x+10)(x-3)

Therefore, D is correct by the Zero Product Property

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Questions linked below
marusya05 [52]

Answer:

The blur of the photo I do not understand sorry

Step-by-step explanation:

ty for the points

5 0
3 years ago
What is the quotient when 4x3 + 2x + 7 is divided by x + 3?
Arte-miy333 [17]

Answer:

The quotient of this division is (4x^2 -12x + 38). The remainder here would be -26.

Step-by-step explanation:

The numerator 4x^3 + 2x + 7 is a polynomial about x with degree 3.

The divisor x + 3 is a polynomial, also about x, but with degree 1.

By the division algorithm, the quotient should be of degree 3 - 1 = 2, while the remainder shall be of degree 1 - 1 = 0 (i.e., the remainder would be a constant.) Let the quotient be a\,x^2 + b\, x + c with coefficients a, b, and c.

4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3).

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is 4 x^3. On the right-hand side, that would be a\, x^3. Hence a = 4.

Now, given that a = 4, rewrite the right-hand side:

\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}.

Hence:

4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)

Subtract \left(4x^3 + 12x^2\right from both sides of the equation:

-12x^2 + 2x + 7 = (b\,x + c)(x + 3).

The term with a degree of two on the left-hand side has coefficient (-12). Since the only term on the right hand side with degree two would have coefficient b, b = -12.

Again, rewrite the right-hand side:

\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}.

Subtract -12x^2 -36x from both sides of the equation:

38x + 7 = c(x + 3).

By the same logic, c = 38.

Hence the quotient would be (4x^2 - 12x + 38).

6 0
3 years ago
Given the lengths of the sides, state if the triangle is acute, obtuse, or right. 8, 15, and 17 This is a(n) blank triangle.
Ivahew [28]

Answer:

This is a right triangle

Step-by-step explanation:

Pythagoras theorem is used to determine if a triangle is right, acute or obtuse

If the sum of squares of two shorter lengths is greater than the square of third side then the triangle is an acute triangle.

If the sum of squares of two shorter lengths is less than the square of third side then the triangle is an obtuse triangle.

If the sum of squares of two shorter lengths is equal the square of third side then the triangle is a right triangle.

so,

(17)^2 = (15)^2+(8)^2\\289 = 225+64\\289=289

Therefore, the given triangle is a right triangle ..

8 0
3 years ago
Ishaan is 3 times as old as Christopher and is also 14 years older then Christopher. How old is ishaan?
rosijanka [135]
I=Ishaan
C=Christopher
I/3=C
I-14=C
Substitute
I/3=I-14
I=3I-42
-2I=-42
Ishann = 21
4 0
3 years ago
Binomial Theorem, proof
IrinaVladis [17]

It follows from the definition of the binomial coefficient:

\dbinom nr=\dfrac{n!}{r!(n-r)!}

So we have

(n+1)\dbinom nr=(n+1)\dfrac{n!}{r!(n-r)!}=(r+1)\dfrac{(n+1)!}{(r+1)!(n-r)!}

That is, (n+1) gets absorbed into the numerator's factorial, and we introduct (r+1) into the denominator. Now, (n+1)-(r+1)=n-r, so we get

(n+1)\dbinom nr=(r+1)\dfrac{(n+1)!}{(r+1)!((n+1)-(r+1))!}=(r+1)\dbinom{n+1}{r+1}

as required.

4 0
3 years ago
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