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Hitman42 [59]
3 years ago
11

Which statement about y = x2 + 7x - 30 is true?

Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

D. The zeros are 3 and -10, because y = (x - 3)(x + 10).

Step-by-step explanation:

y=x^2+7x-30

0=x^2+7x-30

0=(x+10)(x-3)

Therefore, D is correct by the Zero Product Property

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Can you guys help me please
Lemur [1.5K]
C. 7 cm the first triangle is twice the size of the second
4 0
2 years ago
6. Find the value of x.
iris [78.8K]

Answer:

d.51

Step-by-step explanation:

Let the 3rd angle of the triangle be y. Then:

y+117=180

y=63

Then:

x=180-63-66

  =51°

4 0
2 years ago
A scale drawing of a kitchen is shown below. The scale is 1:20.
Viefleur [7K]

Answer:

4×20=80×2=160

5×20=100×2=200

160+200=360

area=360

7 0
3 years ago
I don't understand this question, somebody help
Bas_tet [7]

Answer:

H. 50 sq cm

Step-by-step explanation:

Triangle PSU is an equilateral triangle because each side of it is a radius of semicircle TRP. Also, the radius of semicircle TRP is the short side of the rectangle. So, if the total perimeter of the triangle is 15, each side is 5 cm. So, the short side of the rectangle is 5cm and the long side is 5*2 = 10 cm.

5 * 10 = 50 sq cm

7 0
3 years ago
Read 2 more answers
COMPLETE<br> Find the value of the function for O.<br> sin(45°) = ?
geniusboy [140]

Answer:  \sqrt{2}/2 which is Choice B

This is the same as writing \frac{\sqrt{2}}{2}

The second "2" is not under or inside the square root.

==========================================================

Explanation:

Refer to the unit circle below. I've highlighted the angle 45 degrees and its corresponding sine value. It's the y coordinate of the point on the unit circle, for this particular angle.

Therefore, \sin(45^{\circ}) = \frac{\sqrt{2}}{2}

--------------

You could alternatively draw out a 45-45-90 triangle. Let x be the leg length and the hypotenuse is 1 unit long. Solve x^2+x^2 = 1 for x and you should get x = \frac{\sqrt{2}}{2} as the length of each leg.

Then take the ratio of the opposite over hypotenuse to find the same answer mentioned above.

6 0
1 year ago
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