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2 years ago

Please help asap there both together

Mathematics

2 answers:

antoniya [11.8K]2 years ago

6 0

Answer:

C: Chris made a mistake in step 2.

Step-by-step explanation:

There are 4 main exponent rules in mathematics. In step 1, Chris followed the correct rule of:

$(a^{x})(a^{y})=a^{x+y}$

However, in step 2, he messed up. The correct rule is:

$(a^{x})^{y}=a^{(x)(y)}$

This means that step 2 should have been $4^{-15}$

Hope this helps! :^)

lana66690 [7]2 years ago

4 0

Step 2 , supposed to be 4^-15 instead of 4^-2. Always multiply the exponents together.

Answer: Chris made a mistake in step 2 -C

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Factor out the GCF from the terms of the polynomial −2x5 − 6x3 − 16x2.

Ahat [919]

Answer:

2x^2(x^3+3x+8)

Step-by-step explanation:

Factor out the gcf which in this case is -2x^2 because that's the greatest factor all of the terms have in common this results in -2x^2(x^3+3x+8)

Btw the ^ represents the exponent

4 0

3 years ago

if 42% of a crowd of 3850 at a football match were females, how many females attended the football game?

sweet [91]

Answer: 1617

Step-by-step explanation:

You would need to find 42% of 3850

Convert 42% into decimal:

42/100 = 0.42

Multiply:

0.42*3850

= 1617

Therefore, there were 1617 females that attended the game

7 0

2 years ago

Read 2 more answers

Which symbol correctly compares the fractions below?<br> 6/7 ? 3/4

inna [77]

I belive it would be the > sign

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3 years ago

A publisher displays its latest magizine on its website

IceJOKER [234]

We need to know about unitary method to solve the problem. The length of the actual magazine cover is 8 inches, the width of the actual magazine cover is 11 inches, the length of the new magazine cover is 32cm and the width of the new magazine cover is 44cm.

Unitary method is used to find the value of a unit object. . In this question we know the scale is 6cm to 1 inch for actual magazine cover, the length is given to be 48 cm and the width is 66cm,

length of actual magazine cover= 48/6=8 inches

width of actual magazine cover= 66/6=11 inches

The new scale is 4 cm to 1 inch

length of new magazine cover=8x4=32 cm

width of new magazine cover =11x4=44 cm

Therefore the length of the actual magazine cover is 8 inches, the width of the actual magazine cover is 11 inches, the length of the new magazine cover is 32 cm and the width of the new magazine cover is 44cm.

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Your question was incomplete. Please refer below for the entire question.

A publisher displays its latest magazine cover on its website.

The publisher scales up the front cover of the magazine using a scale of 6 centimeters to 1 inch. The length of the scale drawing is 48 centimeters, and its width is 66 centimeters.

The length of the actual magazine cover is inches.

The width of the actual magazine cover is inches.

The scale drawing is too big to view on a computer screen without scrolling.

the publisher uses a new scale of 4 centimeters to 1 inch.

The length of the new scale drawing is centimeters.

The width of the new scale drawing is centimeters.

7 0

1 year ago

A stereo store is offering a special price on a complete set ofcomponents (receiver, compact disc player, speakers, cassette dec

Korvikt [17]

Answer:

Step-by-step explanation:

(a)

The number of receivers is 5.

The number of CD players is 4.

The number of speakers is 3.

The number of cassettes is 4.

Select one receiver out of 5 receivers in $5C_1$ ways.

Select one CD player out of 4 CD players in $4C_1$ ways.

Select one speaker out of 3 speakers in $3C_1$ ways.

Select one cassette out of 4 cassettes in $4C_1$ ways.

Find the number of ways can one component of each type be selected.

By the multiplication rule, the number of possible ways can one component of each type be selected is,

The number of ways can one component of each type be selected is

$=5C_1*4C_1*3C_1*4C_1\\\\=5*4*3*4\\\\=240$

Part a

Therefore, the number of possible ways can one component of each type be selected is 240.

(b)

The number of Sony receivers is 1.

The number of Sony CD players is 1.

The number of speakers is 3.

The number of cassettes is 4.

Select one Sony receiver out of 1 Sony receivers in ways.

Select one Sony CD player out of 1 Sony CD players in ways.

Select one speaker out of 3 speakers in ways.

Select one cassette out of 4 cassettes in $4C_1$ ways.

Find the number of ways can components be selected if both the receiver and the CD player are to be Sony.

By the multiplication rule, the number of possible ways can components be selected if both the receiver and the CD player are to be Sony is,

Number of ways can one components of each type be selected

$=1C_1*1C_1*3C_1*4C_1\\\\=1*1*3*4\\\\=12$

Therefore, the number of possible ways can components be selected if both the receiver and the CD player are to be Sony is 12.

(c)

The number of receivers without Sony is 4.

The number of CD players without Sony is 3.

The number of speakers without Sony is 3.

The number of cassettes without Sony is 3.

Select one receiver out of 4 receivers in 4C_1 ways.

Select one CD player out of 3 CD players in 3C_1 ways.

Select one speaker out of 3 speakers in 3C_1 ways.

Select one cassette out of 3 cassettes in 3C_1 ways.

Find the number of ways can components be selected if none is to be Sony.

By the multiplication rule, the number of ways can components be selected if none is to be Sony is,

$=4C_1*3C_1*3C_1*3C_1\\\\=108$

[excluding sony from each of the component]

Therefore, the number of ways can components be selected if none is to be Sony is 108.

(d)

The number of ways can a selection be made if at least one Sony component is to be included is,

= Total possible selections -Total possible selections without Sony

= 240-108

= 132

Therefore, the number of ways can a selection be made if at least one Sony component is to be included is 132.

(e)

If someone flips the switches on the selection in a completely random fashion, the probability that the system selected contains at least one Sony component is,

$= \text {Total possible selections with at least one Sony} /\text {Total possible selections}$

= 132 / 240

= 0.55

The probability that the system selected contains exactly one Sony component is,

$= \text {Total possible selections with exactly one Sony} /\text {Total possible selections}$ $\frac{1C_1*3C_1*3C_1*3C_1+4C_11C_13C_13C_1+4C_13C_13C_13C_1}{240} \\\\=\frac{99}{240} \\\\=0.4125$

Therefore, if someone flips the switches on the selection in a completely random fashion, then is the probability that the system selected contains at least one Sony component is 0.55.

If someone flips the switches on the selection in a completely random fashion, then is the probability that the system selected contains exactly one Sony component is 0.4125.

6 0

3 years ago