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2 years ago

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A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the

end of one year, he earned $112 in interest. How much money was invested in each account?
Which of the following equations could be used to solve the problem?

0.02x + 0.04(800) = 112
0.02x + 0.04(x + 800) = 112
0.04x + 0.02(x + 800) = 112

2 answers:

Sonja [21]2 years ago

5 0

In my opinion it could be the last one

sergiy2304 [10]2 years ago

3 0

Answer:

It should be the last one

Step-by-step explanation:

If it's wrong sorry but I'm pretty sure it that one

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$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

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$\sin^2\alpha+\cos^2\alpha=1$

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$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

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$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

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