the roots are
and ![\frac{7-\sqrt{61} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B7-%5Csqrt%7B61%7D%20%7D%7B2%7D)
Step-by-step explanation:
here we use Shridhar acharya formula
if a
+ bx +c = 0 is the quadratic equation
the the roots are ,
and ![\frac{-b -\sqrt{b^{2-4ac} } }{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%20-%5Csqrt%7Bb%5E%7B2-4ac%7D%20%7D%20%7D%7B2a%7D)
comparing with the equation we get a=1 b= -7 c = -3
hence the roots are
and ![\frac{7 -\sqrt{7^{2-4X1X(-3)} } }{2X1}](https://tex.z-dn.net/?f=%5Cfrac%7B7%20-%5Csqrt%7B7%5E%7B2-4X1X%28-3%29%7D%20%7D%20%7D%7B2X1%7D)
=
and ![\frac{7-\sqrt{61} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B7-%5Csqrt%7B61%7D%20%7D%7B2%7D)
The answer in this situation is C. I actually just took the test, and if you look at the graph closely, and do the math correctly, you get C as your answer! ❤️
Answer:
7
Step-by-step explanation:
21=3x
x=7
Translation to the left by 4 units