Answer:
Step-by-step explanation:
It x
Answer:
<em>y = (-mi/h)x + b</em>
y = total distance left to cover
-mi/h = speed at wich he is covering ground
b = the total distance to cover from start to finish
Step-by-step explanation:
Slope Intercept form without other variables filled is shown like this with <em>mx </em>being the slope and <em>b </em>being the y intercept
<em>y = mx + b</em>
all we need to do is fill in known variables with hours multiplied by <em>x </em>represented as <em>m</em>...
<em>y = (-mi/h)x + b</em>
note the negative symbol, this shows that the higher that miles an hour (mi/h) aka speed is, the more distance he will cover REDUCING the distance to cover faster meaning the line will slope DOWNWARD
<em>b</em> would be the the total distance that he has started with, meaning on the point where the line crosses the y axis, the number it crosses at will represent how much he has started with
It appears that your answer contains either a link or inappropriate words. Please correct and submit again!
Answer:
See below. The answer is incomplete, I couldn't post it.
Step-by-step explanation:
Considering a function 
, it is said to be discontinuous when it has a hole or breaks, it means places where 
cannot be evaluated. For example, when the denominator equals to 0, it is not defined.
A. Always because imagine a line where one is y=x and the other is y=-x+1. The point of intersection would be (1,1)
Answer:
Ф = 0 and Ф = π
Step-by-step explanation:
* Lets explain how to solve the problem
∵ sin Ф + 1 = cos²Ф, where 0 ≤ Ф < 2π
- To solve we must to replace cos²Ф by 1 - sin²Ф
∵ sin²Ф + cos²Ф = 1
- By subtracting sin²Ф from both sides
∴ cos²Ф = 1 - sin²Ф
- Lets replace cos²Ф in the equation above
∴ sin Ф + 1 = 1 - sin²Ф
- Subtract 1 from both sides
∴ sin Ф = - sin²Ф
- Add sin²Ф for both sides
∴ sin²Ф + sin Ф = 0
- Take sin Ф as a common factor from both sides
∴ sin Ф(sin Ф + 1) = 0
- Equate each factor by 0
∵ sin Ф = 0
∴ Ф = 0 OR Ф = 2π
∵ sin Ф + 1 = 0
- Subtract 1 from both sides
∴ sin Ф = -1
∴ Ф = π
∵ 0 ≤ Ф < 2π
∵ Ф < 2π
∴ We will refused the answer Ф = 2π
∴ Ф = 0 and Ф = π
