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3 years ago

12

Do you agree or disagree that we should study number systems in computing? Why are Binary and Hexadecimal so important in comput

ing?

1 answer:

yulyashka [42]3 years ago

4 0

Answer: Yes, I agree we should study number system in computing.

Step-by-step explanation:

Hexadecimal numbers can be easily converted to binary numbers.

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Solve for x: 1/2x - 4 = 8

iris [78.8K]

First do 8 + 4 which is 12

Next do 12 times 2 which is 24

Final step is to do 24 divided by 1 which gets you 24

The answer is 24.

5 0

3 years ago

If sam has 1 gallon of milk and he drinks 4 glass of 8 ounces how many dayswould he have drank the milk gone?

Mariulka [41]

1 gallon = 4 quarts

1 quart = 32 ounces, 1 quart = 32 ounces*1 glass/8 ounces = 4 glasses

1 quart = 4 glasses

1 gallon = 4 quarts = 16 glasses

If Sam drinks 4 glasses per day. and he has 16 glasses, then 16/4 = 4 days

Answer is 4 days.

3 0

3 years ago

Diane made a design using only squares she shaded the inner square and outer region find the total area that is shaded explain h

julsineya [31]

You would find the answer by solving shxndbsinsnsndidndnid dbdoamsidbdhdbd

8 0

4 years ago

Tell whether the angles are adjacent or vertical. Then find the value of x. The angles are . Question 2 x=

weeeeeb [17]

Answer:

Adjacent

x = 14

Step-by-step explanation:

Find the diagram attached

Adjacent angles places side by side and can also be on the same straight line. Since 5x and x+96 are on the same straight line ans placed side by side, then the angles are adjacent.

The sum of angle on a straight line is 180 degrees, hence;

5x + x+ 96 = 180

6x = 180 - 96

6x = 84

x = 84/6

x =14

The value of x s 14

8 0

3 years ago

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

3 years ago