Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:
Solve for x
Subtract 8x from both sides
Add 11 to both sides
Divide both sides by 2
2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
Answer: Incomplete question, please edit.
Step-by-step explanation:
Answer:
<u>7 gallons were used for city driving and 17 gallons were used for highway driving</u>
Correct statement and question:
camison's minnan gets 14 miles per gallon for city driving and 19 miles per gallon for highway driving. At the beginning of the week, the 24-gallon tank was full. The family traveled 421 miles before running out of gas. How many gallons were used for city driving and how many were used for highway driving?
Source:
Previous question found at brainly
Step-by-step explanation:
x = Gallons for city driving
24 - x = Gallons for highway driving
Miles drove before running out of gas = 421
Now let's solve for x, writing the following equation:
14x + 19 (24 - x) = 421
14x + 456 - 19x = 421
-5x = 421 - 456
-5x = - 35
x = -35/-5
x = 7 ⇒ 24 -x = 17
<u>7 gallons were used for city driving and 17 gallons were used for highway driving</u>
Answer:
2 x^4
Step-by-step explanation:
Recall that the GCF is the greatest of the product of factors that are common to all these three expressions
then for the pure numerical part, the factor common to 50, -10 , and 2 is "2"
and for the variable part x^4 is the largest common to all three expressions.
Therefore the GCF is: 2 x^4
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