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sashaice [31]
3 years ago
7

Can someone answer the top question? Thanks!

Mathematics
1 answer:
oee [108]3 years ago
5 0

Answer:

Least to greatest:

x-1

x

1-x

-1/x

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1( m² + 15m + 56) = (____) (m+8)<br>2 a² +5ab + 6b²=(a +2b (_____)<br><br>pastor po ​
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Step-by-step explanation:

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{m}^{2}  + 15m + 56 = ( \:  \:  \:  \:  \: )(m + 8) \\ solution \\  \:  \: taking \: lhs \\   = {m}^{2}  + 15m + 5 \\   = {m}^{2}  + (7 + 8)m + 56 \\ \:  \:  \: \:    = {m}^{2}  + 8m + 7m + 56 \:  \:  \\ now \: taking \: common \: factor \\  m(m + 8) + 7(m + 8) \\ (m + 7)(m + 8) \\ now \\  {m}^{2}  + 15m + 56 = (m + 7)(m + 8)

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{a}^{2}  + 5ab +  6 {b}^{2} = ( a + 2b)( \:  \:  \:  \:  \:  \:  \:  \: ) \\ solution \\ taking \:  \: lhs \\  =  {a}^{2}  + 5ab + 6 {b}^{2} \\ =  {a}^{2}  + ( 3+ 2)ab + 6 {b}^{2} \\  =  {a}^{2}  + 3ab + 2ab + 6 {b}^{2}  \\now \: taking \: common \: factor \\ a(a + 3b) + 2b(a + 3) \\ (a + 2b)(a + 3) \\ now \\ {a}^{2}  + 5ab +  6 {b}^{2} = ( a + 2b)( a + 3) ans

this may help you(:

7 0
2 years ago
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