Answer:
The product of the Width and Length is x^2 + 4x + 3 cm^2.
Step-by-step explanation:
The volume of a box = 5x^3 + 20x^2 + 15x cm^3.
Volume of a Box = W*L*H [Width(W), Length(L), and Height(H)]
W*L*(5x) = 5x^3 + 20x^2 + 15x cm^3
W*L = (5x^3 + 20x^2 + 15x cm^3)/5x cm
W*L = x^2 + 4x + 3 cm^2
We know the area of the base of the box (W*L). It is x^2 + 4x + 3 cm^2.
To find the actual width and length, we need to know one of the variables, L or W. Without that, all we can say is that their product (W*L) is x^2 + 4x + 3 cm^2.
Ummmmmmmmmmmmmmmmmm 1,000?
Answer: Choice A) 0.25
How I got that answer:
Count out all of the boxes and you should find there are 8 total. Of this, only 2 boxes weigh less than 26 kg. So we have 2/8 = 1/4 = 0.25
The true statement about R ⊂ A is (a) yes, because all the elements of set A are in set R
<h3>How to determine the set operations?</h3>
The sets are given as:
U = {x | x is a real number}
A = {x | x is an odd integer}
R = {x | x = 3, 7, 11, 27}
From the given sets, we can see that the elements in set R are odd numbers
This means that the set R is a subset of set A
This is represented as:
R ⊂ A
Hence, the true statement about R ⊂ A is (a) yes, because all the elements of set A are in set R
Read more about sets at:
brainly.com/question/2166579
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