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3 years ago

What is the solution for the inequality given below? Show work. 3x - 4 < -19

Mathematics

2 answers:

Ludmilka [50]3 years ago

5 0

Answer:

$x$

Step-by-step explanation:

$3x-4$

Add 4 to both sides

$3x$

Divide both sides by 3

$x$

Hope this helps!

(Please mark brainliest)

Lisa [10]3 years ago

3 0

Answer:

x > - 5

Step-by-step explanation:

3x - 4 < - 19

add 4

3x < - 15

divide 3

x > - 5

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Hello!

We will write and solve this equation below.

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Add 24 to both sides.

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11111nata11111 [884]

Answer:

$\sqrt{8}----- 2units,2units$

$\sqrt{7} ------\sqrt{5}units,\sqrt{2}units$

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Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

$Formula: c^2=a^2+b^2$

1. $a=\sqrt{5}, b=\sqrt{2}$

Plug this into the formula.

$c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }$

The square here eliminates the roots.

$c=\sqrt{5+2}\\ c=\sqrt{7}$

2. $a=\sqrt{3}, b=4$

$c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}$

3. $a=2, b=\sqrt{5}$

$c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3$

4. $a=2, b=2$

$c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}$

5. $a=1, b=2$

$c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}$

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