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2 years ago

If 23 is subtracted from 8 times the number, the result is the square of 2 less than the number.

1 answer:

4 0

I believe the answer is 116.

23-8=15
8*15=120
sqrt2=4
the number 120-4=116

that’s what i got not sure if that is correct

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Sofia and her friends decided to have a water fight on a hot summer day. They filled

gayaneshka [121]

Answer:

3:25pm

Step-by-step explanation:

2:00PM + (40min + 45min) = 85min

hour= 60min

85 - 60 = 25 , its means the amount of the time is 1hour and 25min

1hr25min + 2hr = they finished at 3:25pm

5 0

2 years ago

Find the area of the figure

bija089 [108]

Answer:

Step-by-step explanation:

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A1 = (B + b) x h / 2

A1 = (8 + 2) x 5 / 2

A1 = 10 x 5 / 2

A1 = 25 cm^2

A2 = L x l

A2 = 6 x 8

A2 = 48 cm^2

A = A1 + A2

A = 25 + 48

A = 73 cm^2

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2 years ago

a music store has 40 trumpets 39 clarinets 24 violins 51 fluites and 16 trambones in stock write each ratio in simplest gorm

disa [49]

Given:

A music store has the following:

40 trumpets

39 clarinets

24 violins

51 flutes

16 trombones

We will write the following ratios:

trumpets to violins =

$undefined$

6 0

1 year ago

MATH HELP PLZ!!!

RoseWind [281]

Answer:

a) $tan (157.5) = \frac{1-cos 315}{sin315}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos 330° = 1- 2 sin² (165°)

Step-by-step explanation:

Step(i):-

By using trigonometry formulas

cos2∝ = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ = 2 cos² ∝/2

$cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}$

cos2∝ = 1- 2 sin² ∝

cos∝ = 1- 2 sin² ∝/2

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

Step(i):-

Given

$tan\alpha = \frac{sin\alpha }{cos\alpha }$

we know that trigonometry formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

Given

$tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }$

put ∝ = 315

$tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }$

multiply with ' 2 sin (∝/2) both numerator and denominator

$tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2} }{2sin(\frac{315}{2} cos(\frac{315}{2}) }$

Apply formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

now we get

$tan (157.5) = \frac{1-cos 315}{sin315}$

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 330° above formula

$sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}$

$sin^{2} (165) = \frac{1-cos (330) }{2}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

c )

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 315° above formula

$sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos∝ = 1- 2 sin² ∝/2

put ∝ = 330°

$cos 330 = 1 - 2sin^{2} (\frac{330}{2} )$

cos 330° = 1- 2 sin² (165°)

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2 years ago

The size of a small ant is about 0.002 meters, which can be written as 2 x 10"

Nesterboy [21]

Answer:

Step-by-step explanation:

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6 0

2 years ago

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