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Charra [1.4K]
3 years ago
6

What is the relationship between the 6s in 660,472​

Mathematics
2 answers:
Maksim231197 [3]3 years ago
7 0

Answer:

The value of the first 6 is 10 times that of the second 6.

Step-by-step explanation:

The first 6 is in the hundred thousands place.

The second 6 is in the ten thousands place.

When two identical digits are next to each other in a number, the value of the one on the left is always 10 times that of the one on the right.

Thus, the value of the first 6 is 10 times that of the second 6.

bixtya [17]3 years ago
6 0
The first 6 is 600,00 and the second is 60,000, so they are in the hundred thousands place and the thousands place
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Answer:

∠RQS = 156

Step-by-step explanation:

m∠TQS = 24

∠TQS and ∠RQS are linear pair. Linear pair are two adjacent angles and their sum is 180

∠TQS + ∠RQS = 180

  24 + ∠RQS = 180

         ∠RQS = 180 - 24

        ∠RQS = 156

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35% of f is 14. What is f
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Answer: 40

Step-by-step explanation:

* Hopefully the work below helps:) Mark me the brainliest:)!!

<em>∞ 234483279c20∞</em>

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3 years ago
Find cube root of 175616 ??​
Tpy6a [65]

Answer:

56

Step-by-step explanation:

Cube root of 175616 by prime factorization method is 56

Solution:

To find cube root of 175616 by prime factorization method

A number that must be multiplied by itself three times to equal a given number is called cube root

Prime factorization method:

Prime factorization is a number written as the product of all its prime factors.

In order of finding cube root by prime factorization we use the following steps:

Step I : Obtain the given number

Step II : Resolve it into prime factors.

Step III : Group the factors in 3 in such a way that each number of the group is same

Step IV : Take one factor from each group

Step V : Find the product of the factors obtained in step IV. This product is the required cube root

Prime factorization of 175616:

\text{ prime factors of 175616 } = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 prime factors of 175616 =2×2×2×2×2×2×2×2×2×7×7×7

Thus we get,

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7}

3

175616

=

3

2×2×2×2×2×2×2×2×2×7×7×7

Make the groups of 3 of equal numbers

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{2 \times 2 \times 2 \times } \times \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{7 \times 7 \times 7}

3

175616

=

3

2×2×2

×

3

2×2×2×

×

3

2×2×2

×

3

7×7×7

So there are 4 equal groups. So from that group take one factor out

\sqrt[3]{175616} = 2 \times 2 \times 2 \times 7 = 56

3

175616

=2×2×2×7=56

Thus Cube root of 175616 by prime factorization method is 56

please mark me as a brainlist

3 0
3 years ago
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