-4.5 is your answer, hope this helped
For A I am pretty sure it's 12.6 and for B I believe it's 15.7
Hope I helped
N=25000, p=0.001, np=25000*0.001=25 >10, so the normal approximation should apply.
fewer than 20 => 0,1,2,3...19
Applying the continuity correction, we have X<19.5.
μ=np=25
σ²=npq=25000*.001*.999=24.975 =>
σ=√(24.975)=4.9975
Z(X<19.5)=(19.5-25)/4.9975=-1.100550
P(X<19.5)=P(Z<-1.10055)=0.1355463 [from normal probability table, left tail]
Hence normal approximation to probability that fewer than 20 cars will be stolen is 0.1355.
[actual value by binomial distribution is 0.133450. approximation is quite close]
It 0 maybe this and you can change it when you see it wrong because I'm not seriously with this answer so you can try and work hard to use correct answer thank you
Answer:
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