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Degger [83]
3 years ago
10

If α and β are the zeroes of a quadratic polynomial x²+x-2 then find the value of (α/β+2) (β/α+2)

Mathematics
1 answer:
Korvikt [17]3 years ago
3 0
Βα =  -2 and α+β= -1

(α/β +2)(β/α+ 2)
= 1 + 4 + 2β/α + 2α/β
= 5 + 2(β/α+α/β)
= 5 + 2  [(α^2+β^2) / αβ]
α^2+β^2 = (α+β)^2 - 2αβ =  1 - 2(-2) = 5

SO THE ANSWER IS 5+2(5/-2) = 5 - 5 = 0
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liberstina [14]

Answer:

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Step-by-step explanation:

<u>Prime factors of 2100 are:</u>

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<u>Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:</u>

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So all the numbers from 1 to 7

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Blababa [14]

Answer: 7,308


Step-by-step explanation: 28 X 9 = 252

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6 0
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cestrela7 [59]
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3 0
3 years ago
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