Question

4. For a line whose slope is -3 and which passes through the point (5. - 2)

Answer 1

For point slope form just plug in what is given so you have

m = -3
point (x₁, y₁): (5, -2)

y-(-2) = (-3)(x-(5))
y+2 = -3(x-5)

^for point slope form

for y-intercept form...just solve your point slope equation for y:

y+2 = -3(x-5)
y+2-2 = -3(x-5) -2
y = -3x+15 -2
y = -3x + 13

hope this helps :)