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snow_lady [41]
3 years ago
11

What’s the least common denominator (LCD) for each group of fractions? a. 1⁄6 and 7⁄8 b. 3⁄4 and 7⁄10 c. 7⁄12, 3⁄8 and 11⁄36 d.

8⁄15, 11⁄30 and 3⁄5
Mathematics
1 answer:
erik [133]3 years ago
5 0

Hey there!

\frac{1}{6} And   \frac{7}{8}   \\ \\   LCD: 24  \\ \\ \\ \\ \frac{3}{4}  And \frac{7}{10} \\ \\ LCD: 20 \\ \\ \\ \\ \frac{7}{12}  ,  \frac{3}{8} And \frac{11}{36} \\ \\ LCD: 72 \\ \\ \\ \\ \frac{8}{15} , \frac{11}{30} , And \frac{3}{5}  \\ \\ LCD: 30

Basically "least common denominator" is the number that is the smallest that can be a common denominator to set off the other fractions

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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The graph below shows the distance, y, in miles, of a bird from its nest for a certain amount of time, x, in minutes:
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Answer:

0.2 miles per minute represents the speed of the bird and 3 miles represents the original distance of the bird from its nest.

Step-by-step explanation:

As there is no graph mentioned here but the information are quite sufficient to answer the question.

We have points (0,3), (5,4),(10,5)...

From these points we can find the slope of the line .

From point slope formula y-y_1=m(x-x_1)

And assigning (x,y) (0,3) and (x_1,y_1) (5,4)

m=\frac{y_1-y}{x_1-x} =\frac{4-3}{5-0} =\frac{1}{5}=0.2

This slope is also the speed of the bird which is 0.2\ miles\ per\ minute.

As by plugging the values of any coordinate point we can confirm this.

Lets put (10,5), y-axis is the distance so in 10 minutes the the distance covered by the bird must be equal to to y-axis value which is 5 miles.

y=0.2(x),y=0.2(10)=5\ miles

Now as in t=0 the bird has started from y-intercept value 3 so we can say that,the original distance of the bird from its nest is 3\ miles.

So the correct choices are:B and D

The birds speed is 0.2\ miles per minute and is 3\ miles away from its nest.

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An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

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