The hundredths place value was rounded.
Answer:
The equation does not have a real root in the interval ![\rm [0,1]](https://tex.z-dn.net/?f=%5Crm%20%5B0%2C1%5D)
Step-by-step explanation:
We can make use of the intermediate value theorem.
The theorem states that if
is a continuous function whose domain is the interval [a, b], then it takes on any value between f(a) and f(b) at some point within the interval. There are two corollaries:
- If a continuous function has values of opposite sign inside an interval, then it has a root in that interval. This is also known as Bolzano's theorem.
- The image of a continuous function over an interval is itself an interval.
Of course, in our case, we will make use of the first one.
First, we need to proof that our function is continues in
, which it is since every polynomial is a continuous function on the entire line of real numbers. Then, we can apply the first corollary to the interval
, which means to evaluate the equation in 0 and 1:

Since both values have the same sign, positive in this case, we can say that by virtue of the first corollary of the intermediate value theorem the equation does not have a real root in the interval
. I attached a plot of the equation in the interval
where you can clearly observe how the graph does not cross the x-axis in the interval.
The 5 in x - 5 needs to be negative in the table. So, change that and make everything else in that row negative.
You are then left with 3x^2 + x - 15x - 5
Simplify to 3x^2 - 14x - 5
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Draw a bar and draw little squares inside the box not the bar and then shade the boxes this will represent the number
Answer:
Step-by-step explanation:
Both x and y are inscribed angles. The value of an inscribed angle is half the measure of its intercepted arc. This means that x has a value of 33°, and y has a value of 48°. That means that, according to the triangle angle sum theorem, the third angle has to equal 180 - 33 - 48 = 99°.
This angle is vertical with angle z, so angle z also equals 99°