We know that
• The total is nine starters.
,
• The coach wants to choose three.
Given that the player cannot include repetition, we solve this problem as a combination because the order does not matter.
Where n = 9, and r = 3. Let's replace these values.
<h2>Hence, there are 84 different ways to choose the first three.</h2>
Answer:
H (-2,6)
Step-by-step explanation:
Answer:
27/6, 4 3/6, or simplified version 4 1/2
Step-by-step explanation:
Always convert the mixed numbers into an improper fraction before you solve, this makes it easier to solve.
2 4/6 = 16/6
1 5/6 = 11/6
3 4/6 = 22/6
Now we solve. Remember, you do NOT add the denominator, leave it as 6 not 12. You only add the numerator.
16/6 + 11/6 = 27/6, 4 3/6 or simplified as 4 1/2
22/6 + 5/6 = The same as above.
