<span>3x^2y^2 − 2xy^2 − 8y^2 =
y^2 (3x^2 - 2x - 8) =
factoring with leading coefficient:
for ax2+bx+c find two numbers n,m, that m*n = a*c and m+n = b
</span><span><span>
3x^2 - 2x - 8
a=3, b=-2, c=-8
</span>a*c = 3*(-8) = -24
-24=(-6)*4 and -6+4=-2, so m=-6 and n=4
replace bx with mx + nx and factor by grouping
</span><span>
3x^2 - 2x - 8 = </span>3x^2 -6x + 4x -8 = 3x(x-2) + 4(x-2) = (3x+4)(x-2)
answer:
<span>3x^2y^2 − 2xy^2 − 8y^2 = y^2(3x+4)(x-2)</span>
Idk but the web always helps me so you can ask that question online
Answer:
its 2 1/2 its width
Step-by-step explanation:
Setting up the equation
_______________________
1)Add two x and four x together on the left side. On the right, add 10 and 7.
6x+3=17-x
______________________
Solve:
2)Add x to both sides.
7x+3=17
3) Minus 3 from both sides
7x=15
Divide 15 by seven.
x=<span> 2.14285714286
</span>Hope this helped! Have a happy holiday!
