Let the two required numbers be x and 100 - x, then
Sum of its squares is given by S = x^2 + (100 - x)^2
For the sum of the squares to be minimum, dS/dx = 0
dS/dx = 2x - 2(100 - x) = 0
2x - 200 + 2x = 0
4x = 200
x = 50.
The two numbers is 50 and 50.
Answer:
Step-by-step explanation:
LCM of 4 and 8 = 8
<span>For any point (x, y), that appears in one function, the point (y, x) must appear in the other function.
For any point (x, y), that DOESN'T appear in one function, the point (y, x) must NOT appear in the other function.
So if you find any point that DOESN'T meet the above rules, you can prove that the functions are NOT inverses of each other.
But if you want to prove that they ARE inverses of each other, you have to check ALL points in the functions, and there are infinity of them, so that's not practical. Instead, you can write f(x) like this:
y = 3x - 5
Now solve for x:
y + 5 = 3x
x = (y + 5) / 3
Now swap x and y:
y = (x + 5) / 3
This is the same as g(x). Therefore the functions are inverses of each other.</span>
Answer:
We conclude that:
Step-by-step explanation:
Given the radical expression
simplifying the expression
Remove parentheses: (-a) = -a
Apply radical rule: 
Apply imaginary number rule: 
Apply radical rule: ![\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Csqrt%5Bn%5D%7Bb%7D%2C%5C%3A%5Cquad%20%5Cmathrm%7B%5C%3Aassuming%5C%3A%7Da%5Cge%200%2C%5C%3Ab%5Cge%200)
Apply radical rule: ![\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%2C%5C%3A%5Cquad%20%5Cmathrm%7B%5C%3Aassuming%5C%3A%7Da%5Cge%200)
Therefore, we conclude that:
