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labwork [276]
3 years ago
10

Thirty adults were asked how many pets they have had over their lifetime.

Mathematics
2 answers:
RideAnS [48]3 years ago
5 0

Answer:  mean and  median will lie in the interval 6 -10

Explanation:

mean = \sum_{i=1}^{4} fi*xi/fi

          = (42+64+52+36)/(14+8+4+2)

            =194/28= 6.mean lies in the interval 6-10

for median we have to find n

here n = sum of frequencies /2

n= 28/2=14

so median will lie in the class 6-10

since, it will lie in cumulative frequency of the interval 5-10

so frequency class interval will be one next to cumulative that is 6-10.

madam [21]3 years ago
4 0
The statement that is most likely true is that the median is in the 6-10 interval and the mean is in the 6-10

There were a total of 30 different pieces of data collected, so the 15th and 16th pieces of data that would create the median. Both the 15th and 16th numbers would be in the 6 - 10.

If you find the average of the middle data point in each interval the mean would be approximately 7.2. This is in the 2nd interval (6-10).



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bija089 [108]

Answer:

y²-2y+3

Step-by-step explanation:

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This goes under the divisor.  We then subtract:

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-2y(y+1) = -2y²-2y

We now subtract:

(-2y²+y)-(-2y²-2y) = 3y.  We bring down the last term, 3; this gives us 3y+3.  We divide 3y by y; this is 3.  This goes beside the -2y in the quotient.  We then multiply this by the divisor:

3(y+1) = 3y+3.  We then subtract:  (3y+3)-(3y+3) = 0

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5 0
3 years ago
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Answer:

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Step-by-step explanation:

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What is the answer of (X^2+x-10)-(3x^2-4x-2)=
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