Question

Thirty adults were asked how many pets they have had over their lifetime.

Answer 1

Answer:  mean and  median will lie in the interval 6 -10

Explanation:

mean = $\sum_{i=1}^{4} fi*xi/fi$

          = (42+64+52+36)/(14+8+4+2)

            =194/28= 6.mean lies in the interval 6-10

for median we have to find n

here n = sum of frequencies /2

n= 28/2=14

so median will lie in the class 6-10

since, it will lie in cumulative frequency of the interval 5-10

so frequency class interval will be one next to cumulative that is 6-10.

Answer 2

The statement that is most likely true is that the median is in the 6-10 interval and the mean is in the 6-10

There were a total of 30 different pieces of data collected, so the 15th and 16th pieces of data that would create the median. Both the 15th and 16th numbers would be in the 6 - 10.

If you find the average of the middle data point in each interval the mean would be approximately 7.2. This is in the 2nd interval (6-10).