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SOVA2 [1]
3 years ago
12

Tan x-1/tan x+1=1-cot x/1+cotx

Mathematics
1 answer:
ikadub [295]3 years ago
6 0
\dfrac{\tan x-1}{\tan x+1}=\dfrac{\frac{\sin x}{\cos x}-1}{\frac{\sin x}{\cos x}+1}=\dfrac{\sin x-\cos x}{\sin x+\cos x}=\dfrac{1-\frac{\cos x}{\sin x}}{1+\frac{\cos x}{\sin x}}=\dfrac{1-\cot x}{1+\cot x}
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Step-by-step explanation:

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3 years ago
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Will give brainliest.
lesya692 [45]

Answer:

1. y = \frac{-A}{By}x + \frac{C}{By}

2. Divide the Opposite of A and B

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Step-by-step explanation:

1. Ax + By = C

By = -Ax + C

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3 years ago
A blimp can be seen flying at an altitude of 5500 feet above a motor speedway during a race. The slanted distance directly to th
Vladimir [108]

Answer:

The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}

Step-by-step explanation:

Given as :

The distance of blimp  (AB) = 5500 feet

The slanted distance to the pagoda (BC) = d feet

The horizontal distance (AC) = h

Let the angle made between slanted distance and horizontal distance be Ф

So , cos Ф = \frac{AC}{BC} = \frac{h}{d}

And sin Ф =  \frac{AB}{BC} = \frac{5500}{d}

∵, cos²Ф = 1 - sin²Ф

So, (\frac{h}{d})^{2} = 1 - (\frac{5500}{d})^{2}

Or, (\frac{h}{d})^{2} = (\frac{d^{2}- 5500^{2}}{d^{2}})

Or,                                     h² = d² - 5500²

∴                                        h = \sqrt{d^{2}- 5500^{2}}

Or,                                     h = \sqrt{(d + 5500) (d - 5500)}

Hence The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}     Answer

3 0
4 years ago
How do I add 5 and to together to get an answer
jek_recluse [69]
? You do 5+2= 7
Is that what you are asking
7 0
3 years ago
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Jamie says that the expression 6x-2x+4 and 4(x+1) are not equivalent because one expression has a term that is subtracted and th
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Answer:

1. D 2. A 3. Distribute the four in 4(x+1)

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