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Veronika [31]
3 years ago
8

The starting salary for a computer programmer major has a mean of $39,269 and a standard deviation of $2550. The probability tha

t a randomly selected computer programmer major received a starting salary less than $38,000 is
Mathematics
2 answers:
Nimfa-mama [501]3 years ago
7 0

Answer:

The probability that a randomly selected programmer major received a salary less than 38000 is 0,3085

Step-by-step explanation:

We will assume that the salaries are Normally distributed. Lets call X the salary of a random major programmer in dollars. We want the pprobability of X being less than 38000. For it, we will standarize X. Lets call W the standarization, given by the formula

W = \frac{X-\mu}{\sigma}=\frac{X-39269}{2550}

Lets denote \phi the cumulative distribution function of the standard normal variable W. The values of \phi are well known and they can be found in the attached file. Now, lets calcualte the probability of X being less than 38000 using \phi

P(X

Since the density function of a standard normal random variable is symmetric, then \phi(-0.50) = 1-\phi(0.50) = 1-0.6915 = 0.3085

The probability that a randomly selected programmer major received a salary less than 38000 is 0,3085.

Download pdf
11Alexandr11 [23.1K]3 years ago
3 0

Answer:

The probability is 0.6915

Step-by-step explanation:

Test statistic (z) = (starting salary - mean starting salary)/standard deviation

starting salary = $38,000

mean starting salary = $39,269

standard deviation = $2,550

z = (38,000 - 39,269)/2550 = -1269/2550 = -0.50

The cumulative area of the test statistic is the probability that the starting salary is less than $38,000. The cumulative area is 0.6915.

Therefore, the probability is 0.6915.

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