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Brut [27]
3 years ago
14

I NEED HELP NOW PLEASE!!!! Can you please help me fill out the blanks? I am in need of assistance. I will mark the BRAINLIEST to

the first person who answers correctly.
Provide statements and reasons for the proof of the triangle angle bisector theorem.

Given: BD bisects ABC. Auxiliary EA is drawn such that EA | | BD. Auxiliary BE is an extension of BC.
Prove: AD/DC = AB/BC

You will receive 30 points for answering correctly.

Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0
10 parts of answers
---------------------------

Statement number (2)
From (1) ⇒ BD bisects ∠ABC ⇒ Definition of angle bisects
==========================================
Statement number (3)
Given information 
===========================================
Statement number (4)
Corresponding angles are congruent
=============================================
Statement number (5)
From (2) and (4) ⇒ Transitive property of quality 
=============================================
Statement number (6)
Alternative angles are congruent 
=============================================

Statement number (7)
From (5) and (6) ⇒ Transitive property of quality 
=============================================
Statement number (8)
From (7) ⇒ Δ ABE is an isosceles triangle 
==============================================
Statement number (9)
From (8) ⇒ Definition of the isosceles triangle.
===============================================

Statement number (10)

From (3) ⇒ Triangle proportionality theorem
================================================
Statement number (11)
From (9) and (10) ⇒ Substitution property of equality.

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What does the word distribute mean to you?
Nadusha1986 [10]

In real life when I hear the word distribute, I know that it means that something is being handed out. In business, there is something called a distributor and they hand out stuff from the company that you buy it from. In mathematics, it means that you're giving another number something from another number.

8 0
3 years ago
Find the value of x
fgiga [73]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • x = 35°

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:4x + 1 + x + 4 = 180

[ by linear pair ]

\qquad❖ \:  \sf \:5x + 5 = 180

\qquad❖ \:  \sf \:5(x + 1) = 180

\qquad❖ \:  \sf \:x + 1 = 180 \div 5

\qquad❖ \:  \sf \:x + 1 = 36

\qquad❖ \:  \sf \:x = 36 - 1

\qquad❖ \:  \sf \:x = 35

\qquad \large \sf {Conclusion}  :

  • x = 35°
7 0
2 years ago
5. After paying a tax of 8 palsa per rupee a man saves Rs. 18,400 per month Then his monthly income is 2 Points) 20,000​
Hunter-Best [27]

Answer:

92% of Income is  Rs 18400

Step-by-step explanation:

I = 18400/.92 = Rs 20000

8 0
2 years ago
Coordinates point a​
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I'm sorry cordinate what

6 0
3 years ago
write the given equation into vertex form and sketch the graph. Determine the domain and range f(x)=3x^2-6+2 plss help
LuckyWell [14K]

Answer: the range would thus be [-3, 1/3].)

Step-by-step explanation:

1. To sketch the function f(x) = (2/3)x - 3, we first need to find two points that we can later join to sketch the line, for example the x- and y-intercepts.

a) The x-intercept occurs when f(x) = 0, so if f(x) = 0, then:

f(x) = (2/3)x - 3

0 = (2/3)x - 3

3 = (2/3)x (Add three to both sides)

3*(3/2) = x (Multiply both sides by 3/2)

9/2 = x

We have now found the x-intercept at (9/2, 0)

b) The y-intercept occurs when x = 0, so:

f(x) = (2/3)x - 3

f(0) = (2/3)*0 - 3

f(0) = -3

Now we know that the y-intercept is at (0, -3)

c) All that's left is to sketch the graph axes and label them, plot the two points, join them together using a ruler and label their coordinates.

2. The Domain is the range of x-values for which the function exists, and the Range is the range of y-values for which the function exists.

Since there haven't been any constraints specified, we can say that both the Domain and Range are (-∞, ∞), since the graph continues forever both along the x- and y-axis.

(Note that this isn't always the case and would change if, for example, the question stipulated that there was a domain of [0, 5] and you had to find the range. Then, you would calculate the value of y at each end of the domain (if x = 0, y = -3 and if x = 5, y = 1/3) - in my example, the range would thus be [-3, 1/3].)

4 0
3 years ago
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