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ser-zykov [4K]
3 years ago
7

On a piece of paper, use a protractor and a ruler to construct △ABC with AB=4 in., AC=4 in., and m∠A=60°.

Mathematics
2 answers:
loris [4]3 years ago
4 0

Answer:

Step-by-step explanation:

AysviL [449]3 years ago
3 0

Answer:

Bc=4in

Step-by-step explanation:

Took quizz

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Solve<br> y=-x2+2x+10<br> y=x+4
Marizza181 [45]
Y=10
explanation:
-4•2= -8
2•4=8
-8+8=0
y=10
4 0
3 years ago
Can I get help on this problem showing my work?
Evgen [1.6K]
cost \: of \: 1 \:bracelet \\(no\:shipping): \\72 \: dollars - 9 \: dollars \: shipping = \\ 63 \: \div 9 \: = cost \: of \: 1 \: bracelet \: \\ = 7 \: dollars
\\cost \: of \: shipping: \\ 9 \: dollars \: \div 9 \: bracelets \: = \\ 1 \: dollar\: per\:bracelet \\ \\ formula \: for \: cost \: overall: \\ 7y \: + y

y = quantity, for example:

I want to buy 1 bracelet =
1×7 = 7 + 1 = 8$ per bracelet
6 0
3 years ago
Read 2 more answers
Someone help me . what’s the infinite solution or just what it says help please make sure right .
Gala2k [10]

Answer:

yes it is right

Step-by-step explanation:

3 0
3 years ago
Find the value of x.
Allisa [31]

A straight line is 180°, so you can do:

109 + ? = 180 (? is the top angle of the triangle)

? = 71°

Because the triangle is an isosceles triangle, the other angle is 71° too.

71 + 71 + ? = 180

? = 38

You subtract 38 with 90 to find the other angle.

90 - 38 = 52°

To find ∠2 you subtract 52 with 180.

180 - 52 = 128

∠2 = 128

128 = 11x + 18

110 = 11x

10 = x

5 0
3 years ago
Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$
Viefleur [7K]

QUESTION 1

Given that:

f(x)=2x^2+3x-9,

g(x)=5x+11,

and

h(x)=-3x^2+1

Then;

f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)

f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1

Group similar terms;

f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1

Simplify;

f(x)-g(x)+h(x)=-x^2-2x-19

QUESTION 2

Given that;

f(x)=4x-7.

g(x)=(x+1)^2

and

s(x)=f(x)+g(x)

Substitute the functions;

s(x)=4x-7+(x+1)^2

Substitute x=3

s(3)=4(3)-7+(3+1)^2

s(3)=12-7+(4)^2

s(3)=5+16

s(3)=21

QUESTION 3

Given:

f(x)=3x+2

g(x)=x^2-5x-1

f(g(x))=f(x^2-5x-1)

This implies that;

f(g(x))=3(x^2-5x-1)+2

Expand the parenthesis;

f(g(x))=3x^2-15x-3+2

f(g(x))=3x^2-15x-1

QUESTION 4

The given function is;

f(x)=3(x-6)^2+1

Let

y=3(x-6)^2+1

\Rightarrow y-1=3(x-6)^2

\Rightarrow \frac{y-1}{3}=(x-6)^2

\Rightarrow \sqrt{\frac{y-1}{3}}=x-6

\Rightarrow x=6+\sqrt{\frac{y-1}{3}}

The range is:

\frac{y-1}{3}\ge0

y-1\ge0

y\ge1

The interval notation is;

[1,+\infty)

6 0
3 years ago
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