Question

CIRCLES!! Need help

Answer 1

Answer for the question No.17

Answer:

$x=28.11\ degree$

$m\angle\ ABC=28.11\ degree$

Step-by-step explanation:

Answer for the question No.17

Given:-

$\angle\ BAD=(5x+10)\ degree$

$\angle\ ADC=(87)\ degree$

$\angle\ DCB=(3x+10)\ degree$

Let,$m\angle\ ABC=x$

In quadrilateral ABCD,

$\angle\ BAD+\angle\ ABC+\angle\ DCB +\angle\ ADC =360\ degree$ ---(sum of angle of quadrilateral is 360 degree)

$\therefore\ (5x+10)+x+(3x+10)+87=360$

$9x+107=360$

$9x=360-107$

$9x=253$

$x=\frac{253}{9}$

$\therefore\ x=28.11\ degree$

SInce x=$m\angle ABC$

$\therefore\ m\angle\ ABC=28.11\ degree$