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andre [41]
3 years ago
7

ou are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A a

nd 2% B. What is the ee of this solution
Chemistry
1 answer:
brilliants [131]3 years ago
8 0

Complete Question

You are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the enantiomeric excess?

Answer:

The value is  k  = 96 %

Explanation:

From the question we are told that

   The  percentage of  enantiomer A is  A =  98%

    The  percentage of  enantiomer B is  B =  2%

Generally the enantiomeric excess is mathematically represented as

      k  =  \frac{A -B}{A+B}  *  100

=>   k  =  \frac{98 -2}{98+2}  *  100

=>   k  = 96 %

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