ou are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A a

Question

andre [41]

3 years ago

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ou are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A a

nd 2% B. What is the ee of this solution

Chemistry

1 answer:

brilliants [131] · Answer 1 · 2022-09-05T18:31:31+03:00

Complete Question

You are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the enantiomeric excess?

Answer:

The value is $k = 96 %$

Explanation:

From the question we are told that

The percentage of enantiomer A is A = 98%

The percentage of enantiomer B is B = 2%

Generally the enantiomeric excess is mathematically represented as

$k = \frac{A -B}{A+B} * 100$

=> $k = \frac{98 -2}{98+2} * 100$

=> $k = 96 %$