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SVEN [57.7K]
3 years ago
9

If Kendra started working at 10:30 a.m. and left at 6:15 p.m., how many hours of work should she record for the day on her time

card?
Mathematics
2 answers:
Tom [10]3 years ago
3 0
<span>From 12 PM to 6 PM is 6 hours From 11 AM to 12 PM is 1 hour We are left with 30 minutes (from 10:30 AM to 11 AM) + 15 minutes (from 6 PM to 6:15 PM), so total time (add up what we have) is 7 hours and 45 minutes.</span>
nexus9112 [7]3 years ago
3 0

Answer:

7.75

Step-by-step explanation:

apex

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5 over 8 subtract by 7 over 8
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Since it’s 5/8 minus negative 7/8, the answer is 12/8, you just add them together because the two negative signs cancel each other out.
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If one side of a square notebook measures 20 cm, what is the area of the front cover of the notebook?
GalinKa [24]

Answer:

400 cm squared

Step-by-step explanation:

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Gwar [14]

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I don’t know where to start with this problem
elixir [45]

Answer:

√(4/5)

Step-by-step explanation:

First, let's use reflection property to find tan θ.

tan(-θ) = 1/2

-tan θ = 1/2

tan θ = -1/2

Since tan θ < 0 and sec θ > 0, θ must be in the fourth quadrant.

Now let's look at the problem we need to solve:

sin(5π/2 + θ)

Use angle sum formula:

sin(5π/2) cos θ + sin θ cos(5π/2)

Sine and cosine have periods of 2π, so:

sin(π/2) cos θ + sin θ cos(π/2)

Evaluate:

(1) cos θ + sin θ (0)

cos θ

We need to write this in terms of tan θ.  We can use Pythagorean identity:

1 + tan² θ = sec² θ

1 + tan² θ = (1 / cos θ)²

±√(1 + tan² θ) = 1 / cos θ

cos θ = ±1 / √(1 + tan² θ)

Plugging in:

cos θ = ±1 / √(1 + (-1/2)²)

cos θ = ±1 / √(1 + 1/4)

cos θ = ±1 / √(5/4)

cos θ = ±√(4/5)

Since θ is in the fourth quadrant, cos θ > 0.  So:

cos θ = √(4/5)

Or, written in proper form:

cos θ = (2√5) / 5

4 0
3 years ago
Solve the inequality and graph the solution on the line 5x+7≤-8
bija089 [108]

Answer:

If my calculations are correct.

Step-by-step explanation:

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2 years ago
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