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2 years ago

If x+4/4 = y+7/7 then x/4=___

1 answer:

muminat2 years ago

4 0

Please, enclose those binomials x+4 and y+7 inside parentheses:

(x+4) / 4 = (y+7) / 7. Find (x/4).

Let's solve the above equation for x:

x+4 = 4(y+7)/7. Then x = 4(y+7) / 7 - 4

Last, divide all 3 terms by 4: x/4 = (y+7) / 7 - 1 (answer)

y + 7 - 7
You could also type this as x/4 = ------------- = y/7
7

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Isaiah brought two dozen donuts to a class party. Half of the donuts had vanilla frosting with sprinkles, 2 had strawberry frost

bearhunter [10]

22 donuts had sprinkles.
So 22/24 simplifed to 11/12.

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2 years ago

Read 2 more answers

Use elimination and explain

Temka [501]

Answer:

The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation. So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation

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2 years ago

A train travels 95 kilometers in 1 hours, and then 97 kilometers in 1 hours. What is its average speed?

aleksandrvk [35]

Average speed is given by [Total Distance] ÷ [Total Time]

Average speed = $\frac{95+97}{1+1} = \frac{192}{2}=96$ km/hour

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3 years ago

A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr

Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N Mass of the man, $(m)= \frac{W}{g}$ = $\frac{748}{9.8}$ = $76.32$ kg

Radius of the pond $(r)$ = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is $V_m$ .

Now using law of conservation of momentum we can find the $V_m$ value.

$m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)$

Considering $V_m_(_f_)=V_m$

And initial velocity of both the man and book i.e $V_b_(_i_)=0,\ V_m_(i_)=0$

So,

⇒ $0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m$

⇒ Plugging the values.

⇒ $V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}$

⇒ $V_m=-\frac{1.2\times 4}{76.32}$

⇒ $V_m=-0.062$ ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, $V_m = 0.062$

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know $velocity(v)\times time(t) = distance(d)$

Let the time taken be $t$ and $v\times t = d$ and $d=r$ then, $V_m\times t=r$

Then

⇒ $t=\frac{radius\ (r)}{V_m}$

⇒ Plugging the values.

⇒ $t=\frac{4}{0.062}$

⇒ $t =64$ sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0

2 years ago

The result of which expression will best estimate the actual product

prisoha [69]

Answer:

The answer is,

$(-1) \times \frac {1}{2} \times (-1) \times (1)$

Step-by-step explanation:

The given product is,

$\frac {-4}{5} \times \frac{3}{5} \times \frac{-6}{7} \times \frac {5}{6}$

= $\frac {12}{35}$

$\simeq 0.3429$ ---------------------(1)

Now, the first product to compare is,

$(-1) \times \frac {1}{4} \times (-1) \times (-1)$

= - 0.25 ----------------------------(2)

The second product to compare is,

$(-1) \times \frac {1}{2} \times (-1) \times (1)$

= 0.5 ------------------------(3)

The 3rd product to compare is,

$\frac {-4}{2} \times \frac {3}{2} \times \frac{-2}{5} \times \frac {5}{2}$

= 3 ----------------------------(4)

The 4th product to compare is,

$\frac {-3}{4} \times \frac {-3}{4} \times \frac {-1}{5} \times \frac {1}{2}$

= $\frac {-9}{160}$

= 0.05625 -----------------(5)

Comparing all the values , we get (3) is closest to (1).

Hence, we get, the answer is,

$(-1) \times \frac {1}{2} \times (-1) \times (1)$

3 0

3 years ago