28 tens = 2,800 so 2,800 ones
Answer with explanation:
We have to graph the Linear equation:
→ y-4 =x+2
⇒To draw a line you need two points that lies on the line.
→Point (-2,4) lies on the line,as
L HS→4-4=0
R HS → -2 +2=0
→From Point (-2,4) finding a point which is left 1 unit and down 3 units is equal to = (-2-1 ,4-3)
= (-3,1)
→And from Point (-2,4) finding a point which is left 3 unit and down 1 unit is equal to = (-2-3 ,4-1)
= (-5,3)
→None of the two points that is (-3,1) and (-5,3) lie on the linear function
which is, y-4 =x+2.
≡None of the option
Answer:
20925
Step-by-step explanation:
multiply 675 by 11 to get 7425. Add 7425 to 13500 to get 20925. To check minus 20925 by 7425. I got 13500. So this answer is reasonable.
Answer:
∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° , ∠KLJ = 86°
Step-by-step explanation:
Here, given In ΔJLK and ΔMLP
Here, JK II ML, LM = MP
∠JLM = 22° and ∠LMP = 36°
Now, As angles opposite to equal sides are equal.
⇒ ∠MLP = ∠MPL = x°
Now, in ΔMLP
By <u>ANGLE SUM PROPERTY</u>: ∠MLP + ∠MPL + ∠LMP = 180°
⇒ x° + x° + 36° = 180°
⇒ 2 x = 180 - 36 = 144
or, x = 72°
⇒ ∠MLP = ∠MPL = 72°
Now,as JK II ML
⇒ ∠LJK = ∠JLM = 22° ( Alternate pair of angles)
Now, by the measure of straight angle:
∠MLP + ∠JLM + ∠JLK = 180° ( Straight angle)
⇒ 72° + 22° + ∠JLK = 180°
or, ∠JLK = 86°
In , in ΔJLK
By <u>ANGLE SUM PROPERTY</u>: ∠JKL + ∠JLK + ∠LJK = 180°
⇒ ∠JKL + 86° + 22° = 180°
⇒ ∠JKL = 180 - 108 = 72 , or ∠JKL = 72°
Hence, from above proof , ∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° ,
∠KLJ = 86°
Answer: B) A one sample Z test for a population proportion
Step-by-step explanation: Trust me bro.
