A) let x=months let y=cost y=mx+b y= 20x+ 60 Remember 20 is the variable which means in this case every month it cost 20$ and 60 is the constant which means you only pay it once
B) let x= Months let y= cost y=10x + 150
C) platinum gym y= 20x+60 y=20(1)+60 y=20+60 y=80 Superfit y=10x+150 y=10(1)+150 y=10+150 y=160 Therefore Tom will pay less after the first month
D) y=y solve for x y=20x+60 y=10x+150 20x+60=10x+150 -10x. -10x 10x+ 60=150 -60. -60 10x=90 10x/10=90/10 X=9 9 months Pick any equation and sub in x Y=10x+150 Y=10(9)+150 Y=90+150 Y=240 240$ Know that you only have to do one equation to find y but if you want to show both you can Therefore there is a period where Tom and Edward paid the same amount, after nine months they would both pay $240
E) if they plan on going to the gym 9 months and less the best deal gym is platinum gym but if they want to go for more then 9 months then the best deal gym is super fit
3/-2
I Hoped I Helped
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Divide both sides by 
to get
Substitute 
, so that 
. Then
The remaining ODE is separable. Separating the variables gives
Integrate both sides. On the left, split up the integrand into partial fractions.
Then
On the right, we have
Solving for 
explicitly is unlikely to succeed, so we leave the solution in implicit form,
and finally solve in terms of 
by replacing :
I hope everythink is clearly :) If not just ask :)
answer for your question is starting when x^2-14x-95=0. Just Ignore this above this.
