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Marrrta [24]
4 years ago
10

What is 6 plus 1 as an algebraic expression

Mathematics
1 answer:
Katen [24]4 years ago
5 0
6 + 1 is how you write 6 plus 1 as an algebraic expression
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Give an example of a monomial with a degree of 7.
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Answer:

5x⁷ is a monomial of degree 7

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3 years ago
Mrs. stone is three times older than her younger daughter, Joyce, but only two times older than her older daughter, Alex. how ol
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Answer:

54

Step-by-step explanation:

RSM homework lol

made equation, then solved it.

hope this helps!

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3 years ago
if employee a logged 120 hours of travel in four years and employee b logged hours of travel at 20% higher rate how many more ho
GREYUIT [131]
A 30 hours per year
B 30X(100+20)%=36 per year
1.5 year later is 5.5 years
5.5X36=198 hours
5 0
4 years ago
Find the times (to the nearest hundredth of a second) that the weight is halfway to its maximum negative position over the inter
lesya [120]

Answer:

0.20 and 0.36

Step-by-step explanation:

y(t) = 2 sin (4π t) + 5 cos (4π t)

We wish to convert this to:

y = A sin(ωt + φ)

We know that ω = 4π.  We also know the following:

5 = A sin φ

2 = A cos φ

Divide the first equation by the second equation:

5/2 = tan φ

φ = tan⁻¹(5/2)

Now, square the two equations and add them together.

5² + 2² = (A sin φ)² + (A cos φ)²

29 = A²

A = √29

The equation of the wave is therefore:

y = √29 sin(4π t + tan⁻¹(5/2))

The maximum negative position is -√29.  And half of that is -½√29.

-½√29 = √29 sin(4π t + tan⁻¹(5/2))

-½ = sin(4π t + tan⁻¹(5/2))

7π/6 + 2kπ or 11π/6 + 2kπ = 4π t + tan⁻¹(5/2)

7 + 12k or 11 + 12k = 24t + 6 tan⁻¹(5/2) / π

t = (7 + 12k − 6 tan⁻¹(5/2) / π) / 24 or (11 + 12k − 6 tan⁻¹(5/2) / π) / 24

Trying different integer values of k, we find there are two possible values for t between 0 and 0.5, both when k = 0.

t = (7 − 6 tan⁻¹(5/2) / π) / 24 or (11 − 6 tan⁻¹(5/2) / π) / 24

t ≈ 0.20 or 0.36

6 0
3 years ago
Once each day, Darlene writes in her personal diary And records what is the sun is shining or not. When she looked back through
Deffense [45]
For the initial 600 days the sun was shining for a total of 360 days. This can be found by converting the percentage to a decimal by dividing its value by 100 and then multiplying that value by the initial total number of days shining. 

(60/100) x (600) = 360 days

She then observes the sun for an additional 200 days increasing the total amount of days from 600 to 800. As a result the percentage of sunny days drops from 60% to 50%. To help solve the problem you have to determine what 50% of the new total amount of days is. 

(50/100) x 800 = 400 days 

Lastly to determine how many of the days during the final 200 days were sunny subtract the number of sunny days from the first equation from the second. 

400 days - 360 days = 40 days 

This means that 40 of the final 200 days were sunny. 
8 0
4 years ago
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