All categories

2 years ago

A'B'C' is the image of AABC under a rotation about the origin, ( 0,0).

Mathematics

1 answer:

AnnyKZ [126]2 years ago

6 0

Answer:

90° CCW

Step-by-step explanation:

The angle from C to the origin to C' is a right angle when measured counterclockwise (in the usual direction).

ΔA'B'C' is a rotation of ΔABC 90° CCW.

This is fully equivalent to a rotation of 270° CW.

You might be interested in

What is the solution of n^2 - 49 = 0

Jlenok [28]

N² - 49 = 0
<u>   + 49 + 49</u>
      n² = 49
   n = <u>+</u>7

The solution to the problem is {7, -7}.

5 0

3 years ago

Read 2 more answers

Beth had 1 yard of ribbon she used 1/4 yard for a project she wants to divide the rest into 1/8 yard pieces

Lesechka [4]

She'll have 6/8 yard of ribbon left

3 0

2 years ago

Read 2 more answers

What is the simplest form of 3/24

Finger [1]

The simplest form is 1/8
3/3= 1 24/3 = 8 so 1/8

7 0

3 years ago

Which of the following is a prime number (a).111 (b)91 (c).61 (d).51

marin [14]

Answer:

Step-by-step explanation:

Hope this helps and good luck!:D

4 0

2 years ago

Read 2 more answers

Please help i dont get this at all

Tom [10]

Answer:

$\frac{20y^{2} a^{2} }{41bx^{3} }$

Step-by-step explanation:

1) Flip the second fraction and change the operation to multiplication:

$\frac{5x^{2}y^{3} }{2a^{5}b^{4} } * \frac{8a^{7}b^{3} }{41x^{5}y }$

2) Cross cancel factors:

$\frac{5y^{2} }{2b } * \frac{8a^{2} }{41x^{3} }$

3) Multiply:

$\frac{40y^{2} a^{2} }{82bx^{3} }$

4) Simplify:

$\frac{20y^{2} a^{2} }{41bx^{3} }$

4 0

3 years ago

Read 2 more answers