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timurjin [86]
3 years ago
5

A shipping container is in the shape of a right rectangular prism with a length of 3.5 feet, a width of 10.5 feet, and a height

of 6.5 feet. The container is completely filled with contents that weigh, on average, 0.73 pound per cubic foot. What is the weight of the contents in the container, to the nearest pound?
Mathematics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

Step-by-step explanation:

The shipping container has the shape of a rectangular prism. Therefore, we would apply the formula for determining the volume of a rectangular prism which is expressed as

Volume = length × width × height

From the information given,

Length = 3.5 feet

Width = 10.5 feet

Height = 6.5 feet

Volume of container = 3.5 × 10.5 × 6.5 = 238.875 feet³

If the container is completely filled with contents that weigh, on average, 0.73 pound per cubic foot, then the weight of the contents in the container is

0.73 × 238.875 = 174 pounds

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A store sells a package of 25 trading cars for $5.25. What is the cost of one trading card?
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Answer: 0.21$

Step-by-step explanation: You would do 5.25 divided by 25 to get 21 cents.

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Ahhh helppp i’m almost done with this
MariettaO [177]

Answer:41 m

Step-by-step explanation:

Lets use the Pythagoras thermos to solve

40^2+9^2=c^2

1600+81=c^2

1681=c^2

41=c

The value of the hypotenuse is 41

I see you already attempted this question and got it right, Good job!

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3 years ago
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If roberto can build 1 house in 23 days, how many houses can he build in 207 days?
rusak2 [61]
He would be able to build 9 houses.

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4 years ago
The Dow Jones Industrial Average has had a mean gain of 432 pear year with a standard deviation of 722. A random sample of 40 ye
trasher [3.6K]

Answer:

66.98% probability that the mean gain for the sample was between 250 and 500.

Step-by-step explanation:

To solve this problem, it is important to know the Normal probability distribution and the Central limit theorem.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 432, \sigma = 722, n = 40, s = \frac{722}{\sqrt{40}} = 114.16

What is the probability that the mean gain for the sample was between 250 and 500?

This is the pvalue of Z when X = 500 subtracted by the pvalue of Z when X = 250.

So

X = 500

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{500 - 432}{114.16}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257.

X = 250

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{250 - 432}{114.16}

Z = -1.59

Z = -1.59 has a pvalue of 0.0559.

So there is a 0.7257 - 0.0559 = 0.6698 = 66.98% probability that the mean gain for the sample was between 250 and 500.

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3 years ago
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3/4 of milk: because the bigger the number the smaller the size
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