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timurjin [86]
3 years ago
5

A shipping container is in the shape of a right rectangular prism with a length of 3.5 feet, a width of 10.5 feet, and a height

of 6.5 feet. The container is completely filled with contents that weigh, on average, 0.73 pound per cubic foot. What is the weight of the contents in the container, to the nearest pound?
Mathematics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

Step-by-step explanation:

The shipping container has the shape of a rectangular prism. Therefore, we would apply the formula for determining the volume of a rectangular prism which is expressed as

Volume = length × width × height

From the information given,

Length = 3.5 feet

Width = 10.5 feet

Height = 6.5 feet

Volume of container = 3.5 × 10.5 × 6.5 = 238.875 feet³

If the container is completely filled with contents that weigh, on average, 0.73 pound per cubic foot, then the weight of the contents in the container is

0.73 × 238.875 = 174 pounds

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GrogVix [38]

Answer:

<u>System of equations</u>

x + y = 5

y - 2x = -4

(x,y) = (3,2) --- solution

See attachment for graph

Step-by-step explanation:

Solving (a): Linear equations with 1 solution

The only condition to this is that, the system must have 1 solution.

Other than that, there is no other condition.

A linear equation is represented as:

ax + by= c

For the equation to have 1 solution;

a_1 * b_2 \ne a_2 * b_1

And example of such equation is:

x + y = 5

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Solving (b): The graph

See attachment for graph

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8 0
3 years ago
A group of freshmen at a local university consider joining the equestrian team. Thirty‑five percent of students choose Western r
lesantik [10]

Answer:

a) Option D) 0.75

b) Option D) 0.3

Step-by-step explanation:

We are given the following in the question:

Percentage of students who choose Western riding = 35%

P(w) = 0.35

Percentage of students who choose dressage= 45%

P(d) = 0.45

Percentage of students who choose jumping = 50%

P(j) = 0.50

Percentage of students who choose both dressage and jumping = 20%

P(d \cap j) = 0.20

Percentage of students who choose Western and dressage = 10%

P(w \cap d) = 0.10

Percentage of students who choose Western and jumping = 0%

P(w \cap j) = 0

Thus, we can say

P(w \cap j \cap d) = 0

Formula:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

a) P(student chooses dressage or jumping)

P(d \cup j) = P(d) + P(j) -p(d \cap j)\\= 0.45 + 0.50-0.20 = 0.75

b) P(student chooses neither dressage nor Western riding)

= 1 - P(d \cup w)\\= 1 - (P(d) + P(w) - P(d \cap w))\\= 1 - (0.45 + 0.35 - 0.10)= 0.3

5 0
3 years ago
HELPPPP please thanks!!!
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