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3 years ago

What is the Area of 20ft & 24ft?

Mathematics

1 answer:

olasank [31]3 years ago

7 0

Answer:

480

Step-by-step explanation:

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Rewrite each equation in slope-intercept form, if necessary. Then determine whether the lines are parallel. Explain,

Oksana_A [137]

Answer:
d

Step-by-step explanation:

Slope intercept form: y = mx + b

y = -x + 7
x + y = 21

x + y = 21
-x -x
y = -x + 21

y = -x + 7
y = -x + 21

Parallel lines have the same slope. Here, our slope is -1

Therefore, our final answer is d.

Hope this helps!

8 0

2 years ago

X is at most 30 represent as an algebraic inequality

masya89 [10]

Answer:

x ≤ 30

Step-by-step explanation:

'at most' means the same as 'less than or equal to'.

The sign 'for less than or equal' to is ≤.

So it's simply x ≤ 30.

6 0

3 years ago

Find a 95% confidence interval for the difference in proportions, pt-po, two ways, using StatKey or other technology and percent

beks73 [17]

A bit confusing for me to be able to answer this for you… any way you can simplify your question?

4 0

3 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$