Answer:
in computer science, an instruction is a single operation of a processor defined by the instruction set
Explanation:
if you need anymore help let me know :)
Answer:
1111000
Explanation:
perform the following. write from right to left:
- is the number even? then write down a 0
- is the number odd? then write down a 1 and subtract 1
- divide by 2
- repeat until you reach 0.
So for 120:
120 is even, so write down a 0 and continue with 120/2=60
60 is even, so write down a 0 and continue with 60/2=30
30 is even, so write down a 0 and continue with 30/2=15
15 is odd, so write down a 1 and continue with 14/2=7
7 is odd, so write down a 1 and continue with 6/2=3
3 is odd, so write down a 1 and continue with 2/2=1
1 is odd, so write down a 1 and finish with 0
the output printed on the paper is called hardcopy output. some examples are printer and plotter.
the output produced on display screen and audio sound is called soft copy output. some examples are moniter and speaker.
Do You mean x= x / d ?....because there is no " \ " in math operations
Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.
The Code Given:
import java.util.Scanner;
public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}
