HELP asap please...

Which common online presentation medium do people use to present their own articles?

Nutka1998 [239]

A: news portal hope this helps

7 0

2 years ago

Write a Python function called readlinesmton that accepts the name of the file (i.e. filename), starting line number (i.e. m) an

KatRina [158]

Answer:

Following are the code to the given question:

def readlinesmton(filename, m ,n):#defining a method that holds three parameters

f=open(filename, 'r')#defining f variable that holds open method

l=f.readlines()#defining a variable l that readers input file

e=len(l)#defining e variable lengths of the file

s=m#defining s variable that holds parameter value

if(m<1):#Using if block that checks m is less than 1

s=1#use s variable that holds a value that is 1

if(n < e):#defining n variable that checks n less than e

e=n #using e that holds n value

for i in range(s-1, e, 1):#defining for loop that calculates lines

print(l[i])#prints lines

readlinesmton("input.txt", -1, 70)#Calling a method

Output:

Please find the ouput in the attached file.

Explanation:

In this code, a method "readlinesmton" is declared that takes three-parameter and inside the method, it uses the open method to open the file, read method to read the file, and len to calculate the length of the file and use the conditional statement to check the file inputs and use the loop to prints its values.

5 0

2 years ago

Character positions in arrays start counting with the number 1. True False

d1i1m1o1n [39]

Answer:

False.

Explanation:

A data dictionary can be defined as a centralized collection of information on a specific data such as attributes, names, fields and definitions that are being used in a computer database system.

In a data dictionary, data elements are combined into records, which are meaningful combinations of data elements that are included in data flows or retained in data stores.

This ultimately implies that, a data dictionary found in a computer database system typically contains the records about all the data elements (objects) such as data relationships with other elements, ownership, type, size, primary keys etc. This records are stored and communicated to other data when required or needed.

In Computer programming, an array can be defined as data structure which comprises of a fixed-size collection of variables each typically holding a piece of data and belonging to the same data type such as strings or integers.

This ultimately implies that, when a programmer wishes to store a group of related data (elements) of the same type, he or she should use an array.

Generally, character positions in arrays start counting with the number 0 not 1.

Hence, an array uses a zero-based indexing and as such the numbering or position of the characters (elements) starts from number 0. Thus, the first character (element) in an array occupies position zero (0), the second number one (1), the third number two (2) and so on.

6 0

2 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

Consider the language defined by the following regular expression. (x*y | zy*)* Does zyyxz belong to the language? Yes, because

Mrrafil [7]

Answer:

Consider the language defined by the following regular expression. (x*y | zy*)* 1. Does zyyxz belong to the language?

O. No, because zyy does not belong to x*y nor zy*

2. Does zyyzy belong to the language?

Yes, because both zy and zyy belong to zy*.

Explanation:

4 0

2 years ago

HELP asap please... ​

HELP asap please...