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Musya8 [376]
3 years ago
13

HELP asap please... ​

Computers and Technology
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

I have absolutely no idea bruddah.

Explanation:

Soz!

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'|'/2`/ '|'[] |)[-([]|)[- '|'#!$
natita [175]

Answer: mr Man

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3 years ago
The postorder and preorder traversal of a binary tree are given below - postorder : D E B F G C A preorder : A B D E C F G respe
jeka57 [31]

Answer: The answer is A

Explanation:

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6 0
4 years ago
When an interviewer asks "tell me about yourself", you should tell them about your childhood past. please select the best answer
Yanka [14]

In the interview when the candidate is asked about yourself then telling about childhood past is not correct. Therefore the given statement is false.

<h3>What is an interview?</h3>

An interview is an interaction or a conversation between an employer and the interested candidate. In the conversation the interviewee is asked about their education, family background, and work experiences.

When an interviewer ask about tell me about yourself, then the interviewee should not tell about their childhood past, rather the interviewee should give few information about their family, education, and working.

Therefore, the given statement is false.

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7 0
2 years ago
A photograph is taken by letting light fall on a light-sensitive medium, which then records the image onto that medium.
Andru [333]
True. At least that's how it is for camera's that print photos. Not digital cameras
4 0
3 years ago
Read 2 more answers
⦁ Consider transferring an enormous file of L bytes from Host A to Host B. Assume an MSS of 536 bytes. ⦁ What is the maximum val
timurjin [86]

Answer:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

Explanation:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

8 0
3 years ago
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