Ask question

Ask question

All categories

3 years ago

5

MATH PLEASE HELP

1 answer:

Rom4ik [11]3 years ago

8 0

Answer:

y=6x+8 I think I'm not shure about that.

You might be interested in

Help me answer this one answer

qwelly [4]

The standard formula for the circumference (C) of a circle in terms of its diameter (d) is ...

... C = π·d

6 0

4 years ago

Any suggestions or answers

ryzh [129]

I believe the answer is B.) 9and27/32

Best of luck.

6 0

3 years ago

Read 2 more answers

Which are correct representation of the inequality minus 32X -5 less than 52 minus X select two options

Murljashka [212]

Answer:

The value of X is more than equal to -1.83.

Step-by-step explanation:

We need to find the correct representation of the inequality 'minus 32X -5 less than 52 minus X'

LHS of the inequality will be : -32x-5

RHS of the inequality will be : (52-X)

So,

$-32X-5\leq 52-X$

Adding X both sides

$-32X-5+X\leq 52-X+X\\\\-31X-5\leq 52$

Adding 5 to both sides,

$-31X-5+5\leq 52+5\\\\-31X\leq 57$

Dividing both sides by -31.

$X\geq \dfrac{-57}{31}\\\\X\geq -1.83$

So, the value of X is more than equal to -1.83.

5 0

3 years ago

How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

3 0

3 years ago

IL<br> 8x-9<br> 5x-3<br> What’s x

shepuryov [24]

Step-by-step explanation:

8x-9=5x-3

Move any equation to the opposite side. I'll use the left this time

$8x - 8x - 9 + 9 = 5x - 8x - 3 + 9$

$0 = - 3x + 6$

move 6 to opp side

$- 3x = - 6$

$\frac{ - 6 = - 3x}{ - 3}$

$x = 2$

3 0

3 years ago