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Kay [80]
3 years ago
5

MATH PLEASE HELP

Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0

Answer:

y=6x+8 I think I'm not shure about that.

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(X^2 y^4 z) ^5 / xy^2
DiKsa [7]
X8y18z5 what do you think?
8 0
3 years ago
Please answer 1,2,3, and 4
Anika [276]

Answer:

<u><em>1: "An equilateral triangle is never an obtuse triangle" & "An equilateral triangle is never an isosceles triangle." </em></u>

<u><em> </em></u>

<u><em>2: Acute Isosceles Triangle </em></u>

<u><em> </em></u>

<u><em>3: False! Option B. </em></u>

<u><em> </em></u>

<u><em>4: D</em></u>

Step-by-step explanation:

2: Isosceles Triangles have two equal sides. An acute triangle (or acute-angled triangle) is a triangle with three acute angles (less than 90°). An obtuse triangle (or obtuse-angled triangle) is a triangle with one obtuse angle (greater than 90°) and two acute angles.

3: An <u>equilateral triangle</u> is a triangle in which all the sides and all the angles are equal.

4: In order for a triangle to be <u>isosceles</u>, it has to have two same sides. For a triangle to be <u>equilateral</u>, all sides and angles need to be the same. Refer to reasoning in Question 2 for next explanation.

5 0
3 years ago
Cindy shoots a bottle rocket straight up into the air such that its height h, in feet, at time t, in seconds, is given by the fu
dezoksy [38]

Answer:

t = [0.493,4.2]

Step-by-step explanation:

The height of the rocket straight up into the air is given by :

h(t)=-16t^2+85t+5

We need to find the interval the rocket be at least 43 feet above the ground.

43\ge -16t^2+85t+5\\\\t\ge 0.493\ and\ t\le 4.82\ s

So, the required interval during which the rocket is at least 43 feet above the ground is [0.493,4.2].

6 0
3 years ago
A train leaves at 1314 and arrives at 1508. It travelled at an average speed of 105 km/h.
Paraphin [41]

Answer: The train traveled 199.5 km

Step-by-step explanation:

We know the relationship:

Distance = Time*Speed

We know that the speed of the train was 105km/h

And we know that it leaves at 13:14, and arrives at 15:08.

Then the total amount of time that the train was traveling is:

T = (15 hours and 8 mins) - (13 hours and 14 mins)

= (15 - 13) hours and (8 - 14) mins

=  2 hours and (-6) mins.

We know that one hour has 60 minutes, then this is equal to:

T = 1 hour and 54 minutes.

But because the speed is kilometers per hour, we need to rewrite the 54 minutes in hours.

This can be done as follows:

1 hour = 60 minutes.

Then: 54 minutes = (54/60) hours = 0.9 hours.

Then:

1 hour and 54 minutes = 1.9 hours.

Now we know the speed and the time, then the distance can be calculated as:

Distance = speed*time = 105km/h*(1.9 h) = 199.5 km

The train traveled 199.5 km

3 0
3 years ago
Read 2 more answers
The diameter of a circle is 6 yards. What is the circle's area? d=6 yd Use 3.14 for ​.
madam [21]
The circle's area is 88.74<span>
</span>
6 0
3 years ago
Read 2 more answers
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