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Korvikt [17]
3 years ago
10

14) The height, h metres, of a ball projected directly upwards from the ground can be modelled by h = 56t - 71, where t is the t

ime in seconds after it leaves the ground. a) Find the height of the ball 3.5 seconds after it leaves the ground. b) At what time will the ball strike the ground again? c) When will the ball be 49 m above the ground? Briefly explain why there are two possible answers.​
Mathematics
1 answer:
Agata [3.3K]3 years ago
6 0
Okay the height would be nice if it would have to come
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A survey of 35 individuals who passed the seven exams and obtained the rank of Fellow in the actuarial field finds the average s
arsen [322]

Answer:

150000-2.032\frac{15000}{\sqrt{35}}=144847.94    

150000+2.032\frac{15000}{\sqrt{35}}=155152.06

So on this case the 95% confidence interval would be given by (144847.94;155152.06)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=150000 represent the sample mean

\mu population mean (variable of interest)

s=15000 represent the sample standard deviation

n=35 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=35-1=34

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,34)".And we see that t_{\alpha/2}=2.032

Now we have everything in order to replace into formula (1):

150000-2.032\frac{15000}{\sqrt{35}}=144847.94    

150000+2.032\frac{15000}{\sqrt{35}}=155152.06

So on this case the 95% confidence interval would be given by (144847.94;155152.06)    

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4 years ago
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