Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
2/3x + 4=6. Is that what you mean?
Hello,
Please, see the detailed answer in the attached files.
Thanks.
Top 1. Substitute 3y on both sides of the equation.
Bottom 2. Substitute 2y on both sides of the equation
3y and 2y cancel
Divide x by 4 and 26 by 4.
Is there die points on a graph or decimal?
I have not done this for years but there is many calculators that can show you step by step online. I recommend using these
