A bag contains four red marbles, two Yellow Marbles and five blue marbles.
Two marbles are drawn at random without replacement.
Total number of marbles are,

There are 11 ways to select first marble and 10 ways to select second marble.
The total number of possible outcomes are calculated as,

Thus the total number of possible outcomes are 110.
The answer is 370 because you need to work it out.
Basically what I did was look at the first number, 12, and the answer to the equation and saw that 12 x 10 would be 120. And 360 + 10 would be 370.
It fits in perfectly.
12(370 - 360) = 120
370 - 360 = 10
12(10) = 120
So x = 370
Answer:
161700 ways.
Step-by-step explanation:
The order in which the transistors are chosen is not important. This means that we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

In this question:
3 transistors from a set of 100. So

So 161700 ways.
Find the GCF of 88 and 24 first
88=2*2*2*11
24=2*2*2*3
The GCF for 88 and 24 is 8
The GCF for r^18 and r^13 is r^13 (because they both contain r^13 in them)
=8r^13(11, 3)
Hope I helped :)
Answer: I saw on another post on here with the same question that someone said it was
B. The sum of the volumes of X and Z equals the volume of Y.