7. 4 = 8X + 5Y I need help

Mathematics

1 answer:

ryzh [129]3 years ago

6 0

Are you solving for y? If so thats what im going to do for you.

4 = 8x + 5y

You want to put y by its self do your going to have to subtract 8x.

4 = 8x + 5y

-8x -8x

Then you would get this:

-8x + 4 = 5y

Now all you have to do is divide 5 from y.

-8x + 4 = 5y

5 5

Then you would get;

-8 + 4 = y

5 5

Im sorry if this didnt help but I hope it did! Have a great day! ^^

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The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative

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The true statement is:

"The range of the function is all real numbers less than or equal to 9."

<h3>Which statements are true?</h3>

Here we have the quadratic function:

$f(x) = -x^2 - 4x + 5$

And we want to see which of the given statements are true.

The first one is:

"The domain is al real numbers less than or equal to -2"

This is false, for all quadratic functions the domain is the set of all real numbers (unless the domain is defined).

The second statement is:

" The domain of the function is all real numbers less than or equal to 9."

Also false

Third one:

" The range of the function is all real numbers less than or equal to −2"

The range of a quadratic function with a negative leading coefficient will be the set of all the values smaller than the y-value of the vertex.

In this case, the quadratic function is:

$f(x) = -x^2 - 4x + 5$

So the vertex is at:

$x = 4/(2*-1) = -2\\$