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marishachu [46]
3 years ago
6

write a sequence of transformation that maps quadrilateral ABCD onto quadrilateral ABCD in the picture below please help

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0
It would be a translation and a dilation. I'm sorry if I'm wrong and i can't explain how i know
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A group consists of fivefive men and sevenseven women. FourFour people are selected to attend a conference.
exis [7]

Answer:

Step-by-step explanation:

a.

4 people can be selected in ways=12 P4=12×11×10×9=11880

b.

4 women can be selected in  ways=7P4=7×6×5×4=840

c.

P=\frac{840}{11880} =\frac{7}{99}

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3 years ago
How do you rewrite y-3=4(x-5) turn into Slope Intercept Form
marissa [1.9K]

Answer:

20

Step-by-step explanation:

cause when you do 3=4 equals 4 then multiply 5 then you have 20

6 0
3 years ago
10.04 × 8.8= ?<br><br>can you help me again please​
ANEK [815]

Answer:

10.04 × 8.8 =?, ? = 88.352 :)

7 0
3 years ago
Read 2 more answers
The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml
irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.63}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.63}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

8 0
3 years ago
Given that lines q and m are parallel and are cut by two
sashaice [31]

angle 1 = 180-110 = 70 degrees (linnear pair)

angle 2= 180-115 = 65 degrees (linnear pair)

angle 3 = angle 2 = 65 degrees (corresponding angles)

angle 4= 180 - angle 3 = 180-65 = 115 degrees (linnear pair)

(your teacher might not like this, depends on the cituation, but use 180 degrees in triangle to get 7)

angle 7 = 180 -angle1 -angle 2= 180-70-65= 45 degrees

angle 6 = angle 7 = 45 degrees ( vertical angles)

angle 8= 180- angle 7= 180-45 = 135 ( linnear pair)

angle 9 =angle 6 = 45 degrees (corresponding angles)

angle 5=angle 9=45 degrees (vertical angles)

7 0
3 years ago
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