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marishachu [46]
4 years ago
6

write a sequence of transformation that maps quadrilateral ABCD onto quadrilateral ABCD in the picture below please help

Mathematics
1 answer:
djverab [1.8K]4 years ago
4 0
It would be a translation and a dilation. I'm sorry if I'm wrong and i can't explain how i know
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Find the center and radius for the circle by the equations: x2 + y2 + 5x - y + 2 = 0.
lord [1]
X2+5x+y2-y=-2
X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2
(x+5/2)^2+(y-1/2)^2-13/2=-2
(x+5/2)^2+(y-1/2)^2=9/2
So centre =(-5/2,1/2)
Radius=(9/2)^(1/2)
7 0
3 years ago
Hi! ❤️ , im looking for some help here. ill give brainliest if able to.
Radda [10]
Same question and answer as yours!

8 0
3 years ago
Read 2 more answers
I am confused. The entire question is in the picture.
a_sh-v [17]
Well yes, but it’s in order. The picture will help you solve the questions, the questions are listed in a order so in order to get one question right you have to solve for another question. Like do question 1 before 2 , go in order
8 0
3 years ago
The temperature inside a certain industrial machine at time t seconds after startup, for 0 < t < 10, is given by h(t) = 42
frutty [35]

Answer:

t= \frac{125}{38} s

Step-by-step explanation:

We are given the temperature inside the machine from startup until 10 seconds later, the formula is:

h(t)= 42 \cdot t +1 - 4\cdot t +2  (degrees \, C)

We want to know at what time t the temperature inside the machine will be equal to 128 °C.

So we set:

h(t)=128

42\cdot t+1-4\cdot t+2=128

Now, we rearrange the equation to keep terms with t on the left hand side and terms without t on the right hand side

42\cdot t-4\cdot t=128-1-2

and we simplify:

(42-4)\cdot t= 128-2-1= 125

38 \cdot t = 125

now it's easy to solve for t:

t=\frac{125}{38}

And thus we arrive to the solution.

5 0
3 years ago
Are these correct? ILL MARK YOU BRAINLIEST
Oxana [17]

Answer:

Yes

Step-by-step explanation:

1) Cos 300 = Cos (360 - 60) = Cos 60    {Cos 360 - theta = Cos theta}

                                              = 1/2

Sin 300 = Sin (360 - 60) = -Sin 60 = \frac{-\sqrt{3}}{2}

3) 3π/4 = 3*180/4 = 135

Cos 135 = Cos (90 + 45) = -Cos 45 = \frac{-\sqrt{2}}{2}

Sin 135 = Sin (90 + 45) = Sin 45 = \frac{\sqrt{2}}{2}

7 0
3 years ago
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