All categories

3 years ago

Please help. Will give BRAINLIEST!!!!!

Mathematics

2 answers:

alukav5142 [94]3 years ago

8 0

Answer:

Step-by-step explanation:

Zolol [24]3 years ago

4 0

Answer:

√13

Step-by-step explanation:

if you try Pythagorean's theorem for each one, you should get that √13 doesn't work.

You might be interested in

Someone help please please someone

aev [14]

(1-52/2+5)=(1-26+5)=(-25+5)=-20

continuing:

-20*2*6*6= -40*6*6=-240*6=-1440

result: -1440

6 0

2 years ago

Read 2 more answers

In the school store you can buy 20 calculators for $120 how much would 5 calculators be

Masja [62]

Answer:

30 dollars

Step-by-step explanation:

120/20=6

6x5=30

Hope this helped.

4 0

3 years ago

Read 2 more answers

Solve the problem below. In the space below, show your work, then explain in paragraph form how you solved it. Use precise mathe

vazorg [7]

I also need help on this question. Someone please help out

5 0

2 years ago

Suppose that in a senior college class of 500500 students, it is found that 179179 smoke, 228228 drink alcoholic beverages, 1

olga2289 [7]

Answer: a) 0.16, b) 0.058, and c) 0.856.

Step-by-step explanation:

Since we have given that

Number of students = 500

Number of students smoke = 179

Number of students drink alcohol = 228

Number of students eat between meals = 119

Number of students eat between meals and drink alcohol = 59

Number of students eat between meals and smoke = 72

Number of students engage in all three = 30

a) Probability that the student smokes but does not drink alcohol is given by

$P(S-A)=P(S)-P(S\cap A)\\\\P(S-A)=\dfrac{179}{500}-\dfrac{99}{500}\\\\P(S-A)=\dfrac{179-99}{500}\\\\P(S-A)=\dfrac{80}{500}\\\\P(S-A)=0.16$

b) eats between meals and drink alcohol but does not smoke.

$P((M\cap A)-S)=P(M\cap A)-P(M\cap S\cap A)\\\\P((M\cap A)-S)=\dfrac{59}{500}-\dfrac{30}{500}\\\\P((M\cap A)-S)=\dfrac{59-30}{500}\\\\P((M\cap A)-S)=\dfrac{29}{500}\\\\P((M\cap A)-S)=0.058$

c) neither smokes nor eats between meals.

$P(S'\cap M')=1-P(S\cup M)\\\\P(S'\cap M')=1-\dfrac{72}{500}\\\\P(S'\cap M')=\dfrac{500-72}{500}\\\\P(S'\cap M')=\dfrac{428}{500}=0.856$

Hence, a) 0.16, b) 0.058, and c) 0.856.

5 0

2 years ago

A $45 pair of rainboots is on sale for $38.2. what percent does the customer save?

aksik [14]

Answer:

Step-by-step explanation:

Discount = 45 - 38.20 = $ 6.80

Discount % = $\frac{Disscount}{Original price}*100$

= $\frac{6.80}{45}*100$

= 15.11 %

Percentage of savings = 15.11%

4 0

2 years ago