Answer:
i -j +2k . . . at s=t=-1
Step-by-step explanation:
For the lines to intersect, there must be values of s and t that make the coordinates of r1 equal to those of r2.
Equating i coefficients, we have ...
2 +s = 2 +t
Equating j coefficients, we have ...
2 +3s = 3 +4t
Equating k coefficients, we have ...
3 +s = 4 +2t
The first equation tells us s = t. Using t = s in each of the other two equations, they become ...
2 +3s = 3 +4s ⇒ s = -1
3 +s = 4 +2s ⇒ s = -1
Then the point of intersection is where s = t = -1. That point is ...
(2 +s)i +(2 +3s)j +(3 +s)k = (2 -1)i +(2 -3)j +(3 -1)k
= i -j +2k . . . . the point of intersection
