Question

What is the distance between (-2 1/2,-3) and (1,-3

Answer 1

Answer:

3 1/2

Step-by-step explanation:

pls mark brainliest

Answer 2

Answer:

$3\frac{1}{2}\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$(-2\frac{1}{2},-3)\ and\ (1,-3)$

Convert mixed number to an improper fraction

$2\frac{1}{2}=\frac{2*2+1}{2}=\frac{5}{2}$

so

we have

$(-\frac{5}{2},-3)\ and\ (1,-3)$

substitute the values in the formula

$d=\sqrt{(-3+3)^{2}+(1+\frac{5}{2})^{2}}$

$d=\sqrt{(0)^{2}+(\frac{7}{2})^{2}}$

$d=\frac{7}{2}\ units$

Convert to mixed number

$\frac{7}{2}\ units=\frac{6}{2}+\frac{1}{2}=3\frac{1}{2}\ units$