Answer:
4 and 40
Step-by-step explanation:
2/5 of 10 is 4
2/5 of 100 is 40
Answer:
The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Step-by-step explanation:
This is an example of logistic equation on population growth
carrying capacity, k = 200
Rate, r = 3% = 0.03
Initial Population, P1 = 80
P(t) =?
P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))
P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))
= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))
= 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Answer:
Step-by-step explanation:
Some form of symetric i think....
Answer:
$16.60
Step-by-step explanation:
4 x 0.85 = $3.40
20 - 3.40 = 16.6
Dave should get back $16.60 in change.
Answer:
The temperature with the highest frequency is 54
Step-by-step explanation:
Given
The above data
Required
The temperature with the highest frequency
The first step, is to plot the stem and leaf plot.
Next, is to identify the leaf with the highest frequency.
The leaf is 4 (with frequency 2)
Next, is to identify the accompanying stem of the leaf
The stem is 5
<em>Hence, the temperature with the highest frequency is 54</em>
